13 - Conic Sections: Parabola, Focus, Directrix, Vertex & Graphing - Part 1 - By Math and Science
Transcript
00:00 | Hello , Welcome back to algebra . The title of | |
00:02 | this lesson is called Connick sections , Parabolas Part one | |
00:06 | . So you might be asking why are we talking | |
00:08 | about Parabolas yet again ? And that is because there | |
00:11 | really is a lot more to the concept of parabolas | |
00:13 | than what we have discussed in the past , in | |
00:15 | the past . We've all learned that , why is | |
00:17 | equal to X squared ? Is that basic parabola shaped | |
00:20 | ? And we've grafted , we've sketched them , we've | |
00:22 | talked about how important they are , but now we're | |
00:24 | revisiting in the context of what comic sections are . | |
00:27 | We've already talked about the fact that there are four | |
00:29 | comic sections . We've already talked about circles , that's | |
00:32 | one of the comic sections . Now we're gonna talk | |
00:34 | about Parabolas . Next we'll be talking about ellipses and | |
00:37 | then we'll be talking about hyper Poulos and each one | |
00:39 | of those shapes can be obtained by taking a cone | |
00:42 | . Just a regular old cone and slicing the cone | |
00:45 | in different ways . And I've I've actually done a | |
00:47 | demo of that to show you So again you might | |
00:49 | be saying , why do we care so much about | |
00:51 | Parabolas and specific ? Well it's because Parabolas are all | |
00:54 | around you . The shape of any baseball . When | |
00:56 | you throw it , it kind of arcs up through | |
00:58 | the air and comes back down . That is the | |
01:00 | shape of a parabola . Right ? When you actually | |
01:02 | go into physics and you study motion and how things | |
01:04 | move in gravity , it traces out the shape of | |
01:07 | a parabola . Another example from physics . When you | |
01:10 | learn about energy , kinetic energy , it's called one | |
01:12 | half M is the mass of the object . One | |
01:15 | half M . V squared . So anytime you have | |
01:17 | that square term it's a parabola kind of shape . | |
01:20 | In that case it's energy and velocity . Right ? | |
01:22 | But anyway , these parabolas pop up all over the | |
01:25 | place . So we're going to spend a lot of | |
01:27 | time talking about more detail . Why is that shape | |
01:30 | of the parable is so special ? Why do we | |
01:32 | care ? Why is it so important ? So , | |
01:34 | we're in the beginning we're gonna review what we already | |
01:36 | know about Parabolas . Then I'm gonna give you kind | |
01:38 | of the basic overview of the equations of Parabola in | |
01:41 | terms of other things we're gonna learn called the directories | |
01:44 | and the directorates and the focus of the problem . | |
01:46 | Uh and then we're gonna go through some derivations . | |
01:49 | I'm gonna show you where that shape comes from . | |
01:51 | If I had to boil down this section Into one | |
01:53 | sentence , it would be why is the shape of | |
01:55 | a parable is so special ? And what is that | |
01:58 | shape ? How do we find out what that special | |
02:00 | shape is ? All right , So let's get started | |
02:03 | . We want to talk about the we want to | |
02:06 | recall uh the basic shape of a problem , right | |
02:12 | ? We have done this before , but now we | |
02:14 | are going uh one or two levels deeper into the | |
02:17 | concept of a problem . So we're gonna review really | |
02:19 | quickly what we know . We know . The simplest | |
02:21 | problem that we can have is why is equal to | |
02:24 | X squared ? Or you could replace the Y with | |
02:26 | F . Of X . The function F of X | |
02:28 | is equal to X squared , right ? And this | |
02:30 | parabola is the simplest one that we can have . | |
02:32 | I'm gonna draw a very small autograph here , nothing | |
02:34 | too big here . But if we wanted to draw | |
02:36 | the basic shape of a problem , we know this | |
02:38 | problem touches the X axis , it goes down something | |
02:41 | like this and goes up something like this . It's | |
02:43 | kind of a smiley face notice . Now , this | |
02:45 | is not a perfect drawing , it's got a little | |
02:46 | kink here in the bottom . You can imagine a | |
02:48 | smooth drawing there . The shape of a parabola is | |
02:51 | not a semicircle . A semi circle would be something | |
02:54 | that would go more down like this and more straight | |
02:57 | up . This is much more gradual . Opening is | |
03:00 | what a parabola is now . Of course , that's | |
03:02 | the basic problem . But you know , we can | |
03:04 | change the shape of that Parabola , make it close | |
03:07 | up narrow or open up wider , we can flip | |
03:09 | it upside down so it opens up down and we | |
03:11 | can also take this parabola and we can move it | |
03:13 | anywhere we want in the xy plane just by changing | |
03:16 | the equation of the parabola . So we learned in | |
03:19 | the past that the more general form , the general | |
03:24 | form of the problem , it's something like this , | |
03:28 | It's why minus K . Is equal to a X | |
03:31 | minus H quantity square . Now , if this looks | |
03:34 | unfamiliar to you or totally your lost already and you've | |
03:38 | never seen it before then it just means you need | |
03:40 | to go back to my lessons on Parabolas . We | |
03:42 | talked about that at great length . I did probably | |
03:43 | 10 lessons on it . We talked about what every | |
03:46 | little part of that equation means how to sketch parabolas | |
03:48 | and all of that . But we never talked about | |
03:50 | why the shape of it is so special and why | |
03:52 | it's so important and what the shape of a parabola | |
03:55 | really is . We learned how to sketch it but | |
03:57 | we didn't really talk about why geometrically it works why | |
04:01 | it pops up in nature so much and what's so | |
04:03 | special about it ? So this is the general form | |
04:06 | in an example of that . For an example of | |
04:12 | a practical problem in this form would be something like | |
04:15 | this . Just one example off the top of my | |
04:16 | head . Why minus three is equal to two times | |
04:19 | x minus one quantity squared . So notice you do | |
04:22 | have this x minus one , but this X term | |
04:25 | in general is square . That means it's a parabola | |
04:27 | . The three and the one tell you that this | |
04:30 | parabola is shifted uh in the xy plane , and | |
04:34 | the two in front of the princess tells you that | |
04:36 | it's actually closed up on itself a little more than | |
04:39 | this one right here . So if I were going | |
04:41 | to uh and also because this is a positive number | |
04:44 | out in front , the Parabola opens up if it | |
04:46 | were negative to , it would open down like a | |
04:48 | frowny face . Right ? So the general idea of | |
04:51 | the general shape of this parabola , this is not | |
04:54 | going to be a detailed graph , but just this | |
04:57 | is all review . This is stuff we've done before | |
04:59 | . The x coordinate is shifted one tick mark over | |
05:03 | in the positive one uh direction and then in the | |
05:06 | positive three here and for why 123 So that means | |
05:10 | the bottom of this problem is X is equal to | |
05:12 | one , why is equal to three . We talked | |
05:15 | a long time ago about these minus signs and why | |
05:17 | it shifts it in the positive direction . So we | |
05:19 | know that the vertex the bottom of the problem is | |
05:21 | now here and this problem has a positive too . | |
05:25 | So instead of opening up so broadly like this one | |
05:28 | , I'm just gonna guess here , this is probably | |
05:30 | going to open up a little bit more steeply . | |
05:32 | So you see the higher the number in the front | |
05:35 | of the parentheses , Closes the thing up more . | |
05:38 | If you had 10 or 20 up here it would | |
05:39 | be really , really narrow . And of course if | |
05:41 | it were negative , the whole thing would flip upside | |
05:43 | down and go like a frowny face like this . | |
05:46 | So when this number in front is positive , it | |
05:48 | opens up when this number in front is negative , | |
05:49 | it opens down everything that we have just discussed , | |
05:54 | including the vertex the vertex notice you can read the | |
05:59 | vertex directly out of the equation is one comma three | |
06:02 | , everything one comma three , everything that I've just | |
06:05 | talked about , we've covered at great length already . | |
06:08 | If you don't have any idea what I'm talking about | |
06:09 | it already , then please go back to those lessons | |
06:12 | on parabolas . Our goal now is to go a | |
06:14 | little deeper , that's what we know so far , | |
06:17 | but we want to go a little bit deeper . | |
06:18 | And so to do that , I have a bunch | |
06:20 | of things that I have to cover kind of in | |
06:21 | sequence . Uh and the first thing I wanna do | |
06:24 | is I want to give you a taste . We're | |
06:26 | gonna revisit this board . I almost never ever just | |
06:29 | put things on the board and have you read them | |
06:31 | . I don't like doing that , but in this | |
06:33 | case I have to because there's so much information I | |
06:35 | have to get across , so I have to make | |
06:37 | sure it's all done correctly . Right , So here | |
06:39 | we have the general equations of a problem . I | |
06:41 | want you to ignore everything on the bottom side here | |
06:44 | right now and just focus on the top . Basically | |
06:47 | , this is the general form of a parable equation | |
06:49 | . This purple curve is a parabola , right ? | |
06:52 | The vertex is the lowest point right here . That's | |
06:55 | why it has a V . In the V . | |
06:56 | Is that h comma K . Which is exactly , | |
06:59 | this is the same form of the equation we wrote | |
07:01 | on the other board . So we had y minus | |
07:03 | K and x minus H . Why minus K , | |
07:07 | X minus H . This is exactly what I've written | |
07:09 | on the previous board . So this is all stuff | |
07:11 | we've learned . Um But I guess I just want | |
07:14 | to put it all in one place and tell you | |
07:15 | this is the general form of the equation . This | |
07:18 | whole relation between A and C . I'm gonna get | |
07:20 | come back to a little bit later because notice when | |
07:23 | you get over here uh on the on the on | |
07:26 | the graph , you're gonna notice there's a couple of | |
07:28 | additional things that we never learned about in the past | |
07:30 | . We do have the parabola , but now we | |
07:32 | have a special point above the Parabola called the focus | |
07:35 | . We're going to talk about the focus of the | |
07:37 | parabola in just a minute . So you can think | |
07:39 | of the beams of light if you want to think | |
07:41 | of reflected from that Parabola are focused at a point | |
07:44 | , that's why it's called the focus . The focus | |
07:47 | is not here or here or here or here or | |
07:49 | here . There's only one focus of every Parabola and | |
07:51 | it's exactly at that perfect spot , right ? Just | |
07:53 | think of a focusing light or something . And then | |
07:56 | on the other side of the vertex we have a | |
07:58 | blue line which we call the directory X . I | |
08:01 | don't expect you to know what that is , but | |
08:02 | you just need to know that every Parabola we never | |
08:05 | discussed it before , but every Parabola has associated with | |
08:09 | it . Something called the Focus and also a line | |
08:12 | called the directorates . And we're gonna talk at great | |
08:15 | length what the directorate says , don't stress out about | |
08:17 | it right now . But here you have a purple | |
08:19 | parabola , It shifted some distance in X and y | |
08:22 | . So we have the equation of the thing . | |
08:24 | This is the same equation we learned before . The | |
08:26 | vertex is given . The focus is given . We're | |
08:29 | gonna talk about all of this later . The axis | |
08:31 | of symmetry is given that's where you can cut the | |
08:34 | thing in half . We're gonna talk about that later | |
08:36 | . And then the directorate's I've given here as well | |
08:39 | . Don't worry about what these things mean , I'm | |
08:40 | gonna get to it later . And then this C | |
08:43 | relates to the focus of the parabola , related to | |
08:47 | the number that's in front of the parentheses there . | |
08:49 | Remember when A is greater than zero ? When this | |
08:51 | number is greater than zero . The parabola opens up | |
08:54 | like in our example just a second ago . But | |
08:57 | if the number in front of the problem is negative | |
09:00 | , that's what this means . Then this problem goes | |
09:03 | upside down , right , which we've done in the | |
09:05 | past before . So in general you can have two | |
09:08 | kinds of problems , you can have parabolas that open | |
09:11 | up or down , which is really the only time | |
09:13 | we've discussed so far in this class , but you | |
09:16 | can also have problems that can open left and open | |
09:18 | right and we haven't talked about that before . So | |
09:20 | that's why I say we're going a level deeper . | |
09:22 | So here we have a sketch of a problem that | |
09:25 | in this case opens to the right right . So | |
09:27 | you can see the equation of this parabola is very | |
09:30 | similar to this one really . The only difference between | |
09:32 | these equations is the UAE has been replaced with ex | |
09:36 | and the X . Here has been replaced with Y | |
09:38 | . So when you flip something on its side like | |
09:40 | that , what you're doing is you're interchange in the | |
09:42 | X and Y . Variables . And because if you | |
09:45 | tilt your head sideways , really kind of just pretend | |
09:47 | that this is the X . Axis and this is | |
09:49 | the Y axis then it looks the same is the | |
09:51 | other one . So flipping the variables around , does | |
09:54 | the job of tilting the thing on its side . | |
09:55 | When you do your problems in algebra with problems you're | |
09:58 | gonna have some Prabal is tilted to the side and | |
10:00 | some problems that are going up or down . But | |
10:03 | anyhow this is the equation of a sideways probable . | |
10:06 | You have the same relation between the number in front | |
10:09 | and the focus . We're gonna talk about that later | |
10:11 | . We talk about the vertex and the focus of | |
10:12 | the problem . I'll discuss it later . The axis | |
10:15 | of symmetry cuts this thing in half . I'll talk | |
10:17 | about that later . And then there's an equation for | |
10:19 | the directory which is the blue line here . Okay | |
10:23 | now when A . Is greater than zero , when | |
10:25 | this number is greater than zero , the Parabola opens | |
10:27 | to the right because these are the positive values of | |
10:30 | X . And when it opens with a negative A | |
10:33 | then it's flipped around the other way and it opens | |
10:35 | to the left toward the negative values . That's the | |
10:37 | same thing up here when A is positive , the | |
10:39 | thing opens upwards towards the positive Y . When A | |
10:42 | is negative , it opens upside down to the negative | |
10:45 | towards the negative Y values . So I'm putting all | |
10:48 | this on the board to put it all in one | |
10:50 | place , you have the equation of the problem . | |
10:51 | You have the vertex coordinates , you have the focus | |
10:54 | coordinates , you have the axis of symmetry equation and | |
10:57 | you have the equation for the directorate's noticed that this | |
11:00 | this probably goes up and you have a directorates that | |
11:02 | goes horizontally . This equation has a probably going to | |
11:06 | the right with the focus right here and you have | |
11:08 | a director X behind it . So really if you | |
11:11 | tilt your head is exactly the same picture as what's | |
11:14 | above ? You have focus vertex directory X focus vertex | |
11:18 | directory . Ex I have to put it all there | |
11:21 | because you're going to have to do problems with both | |
11:24 | kind of situations . But what I want you to | |
11:26 | do now is kind of forget about this for now | |
11:28 | . Just in the back of your mind , remember | |
11:30 | , okay , we're going to have to talk about | |
11:31 | horizontal and vertical parabolas , we're gonna have to talk | |
11:34 | about focus , vertex directory , X , axis of | |
11:38 | symmetry . Those are all the things you're gonna have | |
11:40 | to do in all of your homework problems . So | |
11:42 | keep that in the back of your mind that we're | |
11:46 | going to get back to that we're gonna circle back | |
11:48 | at the end of this lesson and you will understand | |
11:51 | everything on that board in exquisite detail , but I | |
11:54 | have to guide you there , okay If I just | |
11:56 | throw it at you and say , hey good luck | |
11:58 | , you'll never do , you'll never know what you're | |
11:59 | doing . So go on a journey with me . | |
12:01 | It's gonna be a little bit of a long lesson | |
12:03 | , but we will get there . So the next | |
12:05 | thing I want to talk about going down that road | |
12:07 | is why is the shape of a parable is so | |
12:10 | important . It's important for lots of reasons , but | |
12:13 | one of the biggest reasons honestly that parabolas are so | |
12:17 | useful in everyday real world um situations is every problem | |
12:23 | has what we call the focus of the preamble . | |
12:28 | Now , a focus of a parabola is very easy | |
12:32 | to understand . But in the back of your mind | |
12:33 | , I want you to remember that when we get | |
12:35 | down to ellipses later on , ellipses have foa foa | |
12:39 | foa foa C two focuses as well . And also | |
12:43 | hyperbole to have focuses as well . So it's not | |
12:46 | like problems . And the only thing that has a | |
12:47 | focus , a parable has one focus one dot . | |
12:50 | And the lips actually has two of those focuses , | |
12:53 | we call emphasize the plural of focus . Uh and | |
12:56 | then hyperbole also have to focus . I so the | |
12:58 | concept of a focus , we're gonna it's gonna stick | |
13:00 | with us as we talk about ellipses , and also | |
13:03 | hyperbole is down the road . And actually the circle | |
13:06 | has a the circle that we've been talking about forever | |
13:09 | . Also has a focus as well . It's just | |
13:11 | the center of the circles . We don't call it | |
13:13 | the focus , we just call it the center . | |
13:15 | Right ? So all of these comic sections have something | |
13:18 | called the focus , right ? But the parable is | |
13:20 | focused is super super important . Now , let me | |
13:23 | try to draw this , It's not gonna be perfect | |
13:26 | , but I'm gonna try to draw a good shape | |
13:28 | problem . Is this a perfect problem ? No , | |
13:30 | it's not . I can almost guarantee you because the | |
13:32 | bottom here is too flat , but it's my best | |
13:35 | shot at a free hand problem . So if this | |
13:38 | were a problem , the focus would probably be somewhere | |
13:40 | right around here . I'm just guessing because I have | |
13:43 | I don't have graph paper and all that . But | |
13:44 | let's just say the focus is right here somewhere . | |
13:47 | Every parabola shape , whether it's really wide open or | |
13:51 | really , really steep , is gonna have one focus | |
13:53 | at one location , right ? The focus is called | |
13:56 | the focus because it takes if you can imagine this | |
13:59 | thing being a radio dish , which is really one | |
14:01 | of the main reasons we use Parabolas in real world | |
14:04 | . We all of your satellite dishes from the gigantic | |
14:07 | radio telescopes , we have all the way down to | |
14:09 | the small satellite dishes for your television or for your | |
14:13 | whatever kind of whatever dishes you see on a tower | |
14:15 | somewhere . They're all Parabolas and the kind of the | |
14:19 | receiver that's in there , or the transmitter is at | |
14:21 | the focus of that Parabola . It's the thing that's | |
14:24 | kind of suspended in the centre , right ? So | |
14:26 | this thing would be the transmitter and the receiver and | |
14:29 | that means that any light waves or radio waves that | |
14:31 | come in are gonna bounce off of this curve surface | |
14:34 | and they're gonna go this direction towards the focus . | |
14:38 | But I also have a light beam , not just | |
14:40 | right here , but I have light beams everywhere . | |
14:41 | I have a light ray coming in here like this | |
14:44 | and it's gonna bounce off that bottom and hit the | |
14:47 | focus as well notice it's curved differently than it is | |
14:49 | right here . If I take another one to the | |
14:52 | other side , it's gonna bounce off and hit this | |
14:55 | right here and I know that it's a little hard | |
14:57 | to see because my parable is not perfect , but | |
14:59 | you can see because it's constantly curving no matter where | |
15:01 | I stick a light beam , it's gonna bounce and | |
15:03 | it's gonna hit this focus point right here , I | |
15:06 | can take one way over here , in fact , | |
15:08 | and it's still going to come off and bounce and | |
15:10 | hit into this guy . So that means that if | |
15:13 | I create a parabola in a special shape of the | |
15:15 | problem and I put the transmitter or the receiver , | |
15:18 | like when you look at the big radio telescopes , | |
15:20 | there's always like the scaffolding with the thing hanging in | |
15:24 | the middle , like above . That's because that's the | |
15:27 | focus of the problem because if I'm going to receive | |
15:30 | light or radio waves from space , it's gonna concentrate | |
15:34 | them at the focus . So I can I can | |
15:35 | hear them better because I'm concentrating on like a magnifying | |
15:38 | glass would concentrate light , right ? Or if I | |
15:41 | want to broadcast something , this whole thing works in | |
15:43 | reverse . If I'm gonna shoot energy out of here | |
15:46 | , no matter which direction I shoot it towards the | |
15:48 | dish is gonna bounce it this direction . So you | |
15:50 | can think of , you know , like the Death | |
15:52 | Star in Star Wars is not a great example , | |
15:54 | but that's kind of like the focus of the of | |
15:56 | the Parabola . You can see it kind of bouncing | |
15:57 | in and going out or coming in and bouncing up | |
16:00 | to the receiver . That's the focus . And as | |
16:03 | I said , Parabolas have a focus . Ellipses have | |
16:05 | Phuoc tuy focuses . Hyperbole also have to focus . | |
16:08 | I so focus is a central thing for comic sections | |
16:11 | , circles have a single focus also , it's just | |
16:13 | at the center right of the thing . All right | |
16:16 | , so this is a useful feature of a parabola | |
16:19 | , but what is the special shape ? Clearly the | |
16:22 | special shape is not a circle . This does not | |
16:24 | look like a semi circle . If you could think | |
16:26 | about a circular shape , what does a circle look | |
16:28 | like to you ? A circle looks something kind of | |
16:31 | like this ? So this means a semicircle is the | |
16:33 | bottom of this thing . A semicircle would be something | |
16:36 | kind of like this actually , that's not even a | |
16:38 | semi perfect semicircle , It should be calling more up | |
16:40 | and down right there . This shape will not reflect | |
16:44 | those rays in the proper way towards a focus . | |
16:46 | Like a parabola . Does it has to be opened | |
16:49 | up more into the shape of a parabola in order | |
16:51 | to bounce everything into the focus right here , That's | |
16:54 | called f the focus point right there . Um But | |
16:57 | the question remains , what is the special shape ? | |
16:59 | What is so special about it ? How do we | |
17:01 | define with the special shape is and how do we | |
17:04 | know that ? Why is equal to X squared ? | |
17:07 | Is that shape that is the special shape that focuses | |
17:10 | things ? That's what we really want to know ? | |
17:13 | Okay , so here I'm going to write the definition | |
17:15 | of the problem , I'm gonna write it right here | |
17:18 | , and I'm gonna draw one more picture to set | |
17:20 | up how we're going to derive this green curve . | |
17:22 | I'm gonna we're gonna actually derive the green curve and | |
17:25 | show that it's equal to this equation or to this | |
17:27 | form of an equation . So the definition of a | |
17:30 | parabola says parabola is the set of all points and | |
17:43 | equal . So I'm gonna underline that an equal distance | |
17:50 | from a point . Yeah , I'm gonna call that | |
17:56 | point to focus . Focus is central to the concept | |
17:59 | of a problem . Uh and a line and this | |
18:05 | special line is called the directors , we're going to | |
18:12 | read this a couple of times , we're gonna let | |
18:13 | it sink in and then I'm gonna draw one more | |
18:15 | picture to kind of set it up . A parabola | |
18:17 | is just a shape . It's the set of all | |
18:20 | points that define that shape . What does that mean | |
18:23 | if this is a circle , all of the points | |
18:25 | along this black curve define what the circle is . | |
18:28 | If this is a Parabola , all of the points | |
18:30 | inside the red curve defined what the curve is . | |
18:33 | If this is a Parabola , all of the points | |
18:35 | that define the green curve define the set of points | |
18:39 | that we call this thing a Parabola . So we're | |
18:40 | seeing a Parabola is the set of all points . | |
18:42 | That means the green curve that are in equal distance | |
18:46 | from a point called the focus . And a line | |
18:49 | called the directorate's . Now I haven't drawn the directorate's | |
18:52 | here , but you can see the focus is here | |
18:53 | , the directory is always somewhere behind the parable . | |
18:56 | In fact when you look , I know I told | |
18:58 | you to forget about this , but if you see | |
19:00 | every parable you have you always have a focus up | |
19:03 | above . And then on the other side of the | |
19:05 | rear end of the parabola , you have this blue | |
19:08 | line called the directorate . So you can kind of | |
19:10 | think of the directorate's is just kind of like this | |
19:12 | blast shield that's kind of a high . If you | |
19:14 | think about this thing is like a death ray or | |
19:16 | something like a gun trying to shoot energy off like | |
19:18 | a death star or something into space or something , | |
19:21 | then it's gonna shoot everything this way and back behind | |
19:23 | it . Is this thing called the Directory . If | |
19:25 | you tilt it off two X . Side , you | |
19:26 | have a focus here . You're shooting your energy out | |
19:29 | this way and you have a directorate that's kind of | |
19:31 | behind it . That's the line that defines the other | |
19:34 | . It's it's in the definition of a parabola to | |
19:38 | define what the shape of a parabola is . In | |
19:40 | other words , another way to say it is if | |
19:43 | I take any line I want and any point I | |
19:46 | want , which I'll call the focus . Then given | |
19:48 | any line and any point I can always choose or | |
19:52 | I can find that beautiful parabolic curve that fits between | |
19:55 | them . Like these do . That is the perfect | |
19:58 | shape of a problem , meaning it will always reflect | |
20:00 | incoming rays to the focus , just like in my | |
20:03 | diagram right here . All right , so let's take | |
20:07 | this definition problem is the set of all points , | |
20:10 | an equal distance from a point called the focus and | |
20:13 | a line called the directory . So let's take those | |
20:15 | words and let's translate them into a picture . And | |
20:18 | then once we translate them into a picture , we | |
20:21 | will have what we need to derive and figure out | |
20:25 | what the shape of this curve actually looks like , | |
20:27 | which is what I'm trying to get before we get | |
20:29 | to that . Let's draw one more picture of this | |
20:33 | whole situation . That will make it a little more | |
20:35 | clear . So I'm gonna redraw what I have above | |
20:38 | with the green curve . Right ? I'm gonna draw | |
20:40 | a parabola and it's not going to be perfect , | |
20:42 | forgive me because I'm not good at drawing things . | |
20:44 | I cannot draw Perfect parable is by hand . So | |
20:47 | , this shape I'm gonna call some kind of problem | |
20:49 | . Okay . Some distance above and kind of inside | |
20:54 | the bowl is some point . A special point called | |
20:57 | the focus that's going to accept all of the incoming | |
21:00 | rays is gonna focus it at that point . So | |
21:02 | this point is called the focus , which we discussed | |
21:06 | before . Right now , the distance between the focus | |
21:11 | and the vertex , which I haven't really talked about | |
21:13 | yet , but there's a point . The lowest point | |
21:14 | of the problem here is called the vertex which we | |
21:19 | discussed when we did parabolas before . So the focus | |
21:23 | is always some distance above the the vertex at some | |
21:30 | distance see . So I'm calling it see , because | |
21:34 | depending on the shape of the parable of the focus | |
21:36 | will be in different locations , but it's got to | |
21:38 | be some distance above it . So we just call | |
21:40 | that distance , see . But whatever distance this is | |
21:43 | right here , there's always a special line on the | |
21:46 | back side underneath the rear end which we call the | |
21:49 | directorate's , it's always a line that goes horizontal . | |
21:53 | If it's a horizontal probable a vertical , if you | |
21:55 | understand what I mean . If it opens upwards , | |
21:57 | it's a horizontal line . If it opens sideways , | |
21:59 | it's a vertical line . But the interesting thing and | |
22:02 | the special thing is that the distance between the vertex | |
22:06 | is also a distant sea to the directorate . So | |
22:09 | this thing is called the directorate's Mhm . Okay , | |
22:16 | so it's crucially important for you to understand that the | |
22:19 | vertex is always halfway between the focus and the directorate's | |
22:24 | I'm gonna say that again , the vertex , the | |
22:27 | lowest point of the problem is always halfway between the | |
22:31 | focus and the directorate's I'm gonna say it a third | |
22:33 | time , the vertex is always halfway between the focus | |
22:37 | and the director . So here's the focus . Here | |
22:39 | is the Director X . This is a distant sea | |
22:41 | , This is a distant sea . So the vertex | |
22:43 | has to be in the middle , right . It's | |
22:45 | always halfway between like this . So I can even | |
22:48 | write that down and I can say the vertex Is | |
22:50 | always 1/2 the way the between focus and direct tricks | |
23:03 | . So now we have a pretty complete picture , | |
23:04 | we have a parabola drawn on the board , we | |
23:07 | have a focus of the Parabola which is going to | |
23:09 | focus all the incoming light beams or radio waves . | |
23:11 | We have a directorates which sits on the back side | |
23:14 | and we're saying that there's a special shape which is | |
23:17 | the blue curve which we call a parabola . And | |
23:19 | we're saying the definition of a parabola is the set | |
23:21 | of all points . That's the blue line , an | |
23:23 | equal distance from the focus and the Director X an | |
23:28 | equal distance from the focus . And the directorate's , | |
23:30 | I'm saying it again to get it into your head | |
23:33 | . A parabola is the set of all points for | |
23:35 | that blue curve . That is always every point on | |
23:38 | that curve is always an equal distance between the focus | |
23:42 | and that line that we call the directory . So | |
23:45 | let's talk about how we make that happen . What | |
23:47 | this thing is saying is that this blue curve is | |
23:52 | the set of all points . Were calling a problem | |
23:54 | , The distance between this focus to this point on | |
23:59 | the problem is the same as the distance between this | |
24:02 | and this . Now if you my drawing is not | |
24:05 | perfect . So it looks to me like this line | |
24:07 | is a little bit shorter than this one . But | |
24:09 | if I had opened up my problem or maybe move | |
24:11 | my focus a little bit more , exactly this line | |
24:14 | should be exactly the same as this one . Now | |
24:16 | , in geometry , the way you denote two lines | |
24:19 | being congruent is what we call it . A geometry | |
24:21 | . We're gonna put a little line through there . | |
24:23 | In the line through there . That means this distance | |
24:24 | is the same as this one . This one that | |
24:27 | means that the parable is the set of points . | |
24:29 | That's an equal distance from the focus and the directory | |
24:32 | . So this is an equal distance . This point | |
24:34 | here is an equal distance to the focus . And | |
24:37 | also to the directorate's What if I pick a different | |
24:39 | point on this Parable ? What we're saying is from | |
24:42 | here and then straight down here are equal distances . | |
24:46 | This point on the curve we're calling the parable is | |
24:49 | an equal distance to the focus as it is to | |
24:51 | the directorate's . What if we go crazy , we | |
24:54 | pick a point way over here . Well , that's | |
24:56 | okay , This is farther away . Sure , it | |
24:58 | is . But so is this one this one's farther | |
24:59 | away to the black line . So this is an | |
25:01 | equal distance from there . And they're now of course | |
25:04 | it doesn't just happen on the left hand side . | |
25:06 | It happens on the right hand side too . So | |
25:07 | I'll go ahead and draw one going way over here | |
25:10 | and then won going away over here . This distance | |
25:13 | is the same as this one . So you can | |
25:15 | see that what we have done is effectively we've picked | |
25:19 | a focus in space and then we've picked a Directory | |
25:22 | X . And when you pick a focus and you | |
25:24 | pick a directorates , there always has to be a | |
25:26 | special curved path that goes between them where the bottom | |
25:30 | of the thing goes directly between the focus and the | |
25:32 | directory X . Right . But there has to be | |
25:34 | a special shape so that every single point on this | |
25:37 | blue curve , every point on this curve is an | |
25:40 | equal distance to the focus as it is to the | |
25:42 | directorate's equal distance to the focus as it is to | |
25:45 | the directory at this point at this point this point | |
25:47 | this point this point every point is always an equal | |
25:49 | distance from the focus to the directorates . And that | |
25:53 | is why Parabolas focus energy towards the focus . Focus | |
25:57 | , incoming parallel rays to the focus . Because it's | |
26:00 | especially constructed shape that always is the same distance to | |
26:04 | the focus to the directorates . And when you do | |
26:06 | the math and go through how everything is reflected . | |
26:08 | It turns out that that focuses all of the incoming | |
26:11 | energy into a point we call the focus and that's | |
26:14 | why we call it the focus . This kind of | |
26:16 | thing is not what you learn when you first learned | |
26:19 | about what a parabola is . We talk about a | |
26:20 | parabola , why is equal to X square ? You | |
26:23 | just say , oh , it's a problem . Great | |
26:24 | , we graph it , we talk about it , | |
26:26 | you know , even in calculus , you learn how | |
26:28 | to do things with parabolas , but until you get | |
26:31 | to a lesson like this , you don't understand why | |
26:33 | we care about perhaps why they're so special . A | |
26:36 | circle is another special shape . It's the set of | |
26:39 | all points in equal distance from the center , an | |
26:42 | equal distance from a single point . That's what we | |
26:44 | call the special shape called a circle . A parabola | |
26:47 | is a special shape where every point on that curve | |
26:50 | is an equal distance to the focus as it is | |
26:52 | to the directorate . So every parabola has a director | |
26:55 | X . Every parabola has a focus and that's something | |
26:58 | you have to get in your head . We first | |
27:00 | learned about Parabolas , we don't talk about the focus | |
27:03 | or the directorate . So it kind of seems like | |
27:05 | we're adding it on . But in fact every parable | |
27:07 | you've ever graft always had a directorates , even if | |
27:10 | you didn't graph it and they always had a focus | |
27:12 | , even if you didn't graphic . But here in | |
27:14 | these problems moving forward , we're always going to talk | |
27:17 | about the focus and the Director X as we graph | |
27:20 | and sketch all of these problems . So we have | |
27:23 | reviewed basically what we knew about Parabolas , we have | |
27:27 | introduced the equations of a parabola , but I haven't | |
27:31 | really explained a lot about this because I need to | |
27:33 | talk about a few more things before I go into | |
27:35 | crazy detail here . But now at least you understand | |
27:37 | a little bit more that every problem has a focus | |
27:40 | , It has a direct tricks , the distance C | |
27:43 | . Is here , the distance C . Is here | |
27:44 | . So the vertex is halfway between the focus and | |
27:47 | the director . Same here . The vertex is halfway | |
27:50 | between the director and the focus for every problem that | |
27:53 | we have and so we've learned all of these things | |
27:56 | and then finally we talk about this special uh property | |
27:59 | of a problem which allows to focus incoming parallel rays | |
28:02 | to a point . And then we talked about the | |
28:04 | definition of a problem , which we've discussed a lot | |
28:08 | so that you can get your brain wrapped around it | |
28:10 | now . But we need to do is we need | |
28:12 | to derive the shape , the equation of a parabola | |
28:15 | . See , here's the geometric description , here's a | |
28:17 | point . We call the focus , here is a | |
28:19 | line called the directorate's . There has to be some | |
28:21 | blue curve called a parabola that every point on this | |
28:24 | curve is an equal distance from the point here to | |
28:27 | the focus . And the point here to the directorate's | |
28:29 | there has to be some special curve we call a | |
28:31 | parable . What is the equation of that curve ? | |
28:34 | Now , you already know the answer . The equations | |
28:36 | of a parable . Always look like this . But | |
28:38 | how do we go from the definition of the parabola | |
28:41 | , which is all about geometry to showing that really | |
28:44 | ? This thing is and does describe all parabolas that | |
28:47 | you can graph . How do we know that ? | |
28:49 | And so what we're gonna do is we're gonna go | |
28:51 | through a derivation of that . It's not hard , | |
28:53 | it's actually really easy to understand , but I do | |
28:56 | have to do some drawings here in the beginning . | |
28:59 | Uh so we're just gonna jump right into it . | |
29:01 | So what we have is we have to draw another | |
29:03 | sketch before we can derive the equation of a problem | |
29:06 | . And this sketch , I'm gonna draw right at | |
29:08 | the top of the board . It's not going to | |
29:09 | be very um uh long here , but I do | |
29:14 | need to get it on the board . So here | |
29:15 | we have the xy plane . I'm trying to give | |
29:17 | myself a lot of space down here to do the | |
29:19 | rest of the work . So here we have the | |
29:21 | xy plane . Now I have to pick some actual | |
29:24 | numbers . So what I'm gonna do is I'm gonna | |
29:27 | put the uh the focus of this parabola at 123 | |
29:33 | units along the X axis . So this thing is | |
29:35 | called the focus , it's at three comma zero , | |
29:38 | right ? And then I'm gonna put the vertex At | |
29:43 | 3:02 . So this is the vertex at 3:00 to | |
29:48 | now because this is the vertex and because this is | |
29:50 | the focus , you know that the problem has to | |
29:53 | be opening upside down because the focus is always kind | |
29:57 | of inside the Parabola , the focus is always inside | |
29:59 | the bowl . So if the vertex is here and | |
30:02 | the focus is here , the only way the thing | |
30:03 | works is if it goes something like this and I'm | |
30:05 | gonna try to draw upside down the best I can | |
30:09 | . Is this perfect ? No , it's not . | |
30:10 | I can already tell this kind of opened up a | |
30:12 | little bit weird . But anyway , that's the basic | |
30:14 | problem . This is the highest point of the actually | |
30:16 | , I'm looking at it again , it's completely lopsided | |
30:18 | . Sorry about that actual let's try to let's try | |
30:20 | to fix it just a little bit . So it's | |
30:23 | gonna go off something like something like this . Still | |
30:27 | not great . Sorry about that . Anyway , it's | |
30:30 | an upside down parabola that goes something like this . | |
30:34 | All right now , every problem has a focus and | |
30:38 | every problem also has a directory . So let me | |
30:40 | ask you if the focus is here and the vertex | |
30:43 | is here , where is the director of this problem | |
30:47 | ? The Director of the problem has to be on | |
30:49 | the other side has been on the backside . And | |
30:51 | also we said that the vertex is always halfway between | |
30:54 | the focus and the directorates . So if the focus | |
30:57 | is here , the vertex is here , the directorate's | |
30:59 | has to be the same distance away on the other | |
31:01 | side . So that means that uh we have 12 | |
31:07 | so this is three , this is four . So | |
31:09 | that means it needs to be a horizontal line up | |
31:11 | here . This is going to be the directory . | |
31:13 | So I'm gonna write this Director X . And what | |
31:17 | is the equation of this directory ? X . Well | |
31:20 | , this is 1 , 3 , 4 . So | |
31:22 | this equation of directions , Directorates is y is equal | |
31:25 | to four , it's a horizontal line , four units | |
31:27 | up like this . How do we know the director | |
31:29 | is actually there ? It's because the vertex always has | |
31:33 | to be in the middle , So , if this | |
31:34 | is two units , that this has to be two | |
31:35 | units . And so when we locked down the vertex | |
31:38 | we are , we know where the director says a | |
31:40 | lot of these problems in algebra , always gonna be | |
31:42 | like , tell me where the vertex is , and | |
31:44 | you'll just have to know how things are set up | |
31:47 | their equal distance on either side of the vertex or | |
31:49 | whatever to write . The equation of the directorate's down | |
31:51 | , which is what we did right here . All | |
31:55 | right . So , what we need to do is | |
31:57 | we need to realize that this blue curve is a | |
32:02 | bunch of points , right ? It's a bunch of | |
32:04 | points . Um And so what we're saying is that | |
32:08 | this point , for instance , right . Whatever this | |
32:11 | point is right here , I don't know exactly where | |
32:12 | it is . It's over here and it's up here | |
32:14 | , but there's some point right there in the curve | |
32:16 | of the problem , right ? But I do know | |
32:18 | one thing and that is the distance from here to | |
32:20 | here to the focus is the same as the distance | |
32:23 | up like this , and I'm gonna put little lines | |
32:25 | to show me this . So this line Here , | |
32:29 | D one is the point on the direct tricks right | |
32:32 | there . And what I'm saying is that the distance | |
32:36 | between this point and the line directory is the same | |
32:40 | as the distance here to here . Now , I | |
32:41 | can tell you that they don't look the same because | |
32:43 | I'm drawing it freehand . But if you can imagine | |
32:46 | that I opened my problem up a little bit more | |
32:48 | and it was an exact shape , then it would | |
32:50 | exactly be correct , Right ? And then if you | |
32:53 | want to pick another point , let's say at this | |
32:54 | point right here , and this one even looks uh | |
32:57 | looks even worse actually . You can see because this | |
33:00 | one here , what I'm saying is the same as | |
33:02 | the distance up there as well . It doesn't look | |
33:04 | the same . And that is just because my parabola | |
33:07 | is really just to it's too crunched and it's not | |
33:10 | a real Parabolas shape . So if I wanted to | |
33:11 | fix it , I could erase this and you know | |
33:13 | , we could do that if you want . Doesn't | |
33:15 | really matter too much . No , but you know | |
33:17 | why not ? Let's just open it up , just | |
33:19 | a little bit more . Something like this , that's | |
33:21 | probably a little bit closer . Is it still exact | |
33:23 | ? No , it's not exact , but it's pretty | |
33:25 | close . So let's go and do something . Like | |
33:28 | let's try to erase this a little bit . So | |
33:29 | the distance here to here is the same as distance | |
33:32 | here . To hear the distance here to here is | |
33:34 | the same as distance here and here . That's pretty | |
33:36 | close . And we'll call this point D . Sub | |
33:39 | two because that's where it hits that line . And | |
33:42 | we'll call we'll do one more point this point here | |
33:44 | . The distance between here and the focus is the | |
33:47 | same as the distance up there to the directory . | |
33:50 | So those lines are there and then this one I'm | |
33:53 | gonna label as an actual point . I'm gonna label | |
33:56 | this one right here , I'm gonna call it P | |
33:59 | . X . Comma Y . And then up here | |
34:02 | this deed is going to be the point on the | |
34:04 | directorate's is an X . Comma . For now I | |
34:07 | need to explain what I'm talking about here because pretty | |
34:09 | soon I'm gonna use this in an equation . What | |
34:12 | I'm saying is the focus is a lockdown point at | |
34:14 | 3:00 . The point on the Parabola is just some | |
34:19 | X . Y . Location . If I look at | |
34:21 | all these points here , they are all at different | |
34:23 | X . Y locations . I don't know what this | |
34:25 | point P . Is because I don't know the shape | |
34:27 | of the curve yet but it's at some X . | |
34:28 | Y . Location . Okay , this point here is | |
34:32 | the same X . Value is the point because it's | |
34:34 | straight up . That's why X . Is the same | |
34:36 | here . But it's four units and why ? That's | |
34:39 | why I had to put the number four here . | |
34:40 | So it's an X . Comma fourth . In other | |
34:43 | words the point where I intersect here is that whatever | |
34:46 | the point is here X . Comma four units up | |
34:50 | now . Why do I spend all of this time | |
34:52 | writing this stuff down ? And that is because what | |
34:54 | we need to do is figure out the equation of | |
34:57 | this parabola . We want to derive this thing and | |
35:00 | we know that the definition means that the distance from | |
35:03 | every point on this parabola to the focus and also | |
35:06 | to the directory is the same distance . So that | |
35:09 | means if this is a point F , the distance | |
35:12 | between F and P is the same thing as the | |
35:16 | distance between P and D . This distance is the | |
35:19 | same as this distance . This distance is the same | |
35:21 | as this distance . This one is the same as | |
35:23 | this one . This one is the same as this | |
35:24 | one . This one is the same as this one | |
35:26 | . Every point I pick on this parabola then the | |
35:29 | distance from the focus to the point on the parable | |
35:32 | is the same as from that distance from that same | |
35:34 | point to the directory , X F p is equal | |
35:37 | to P . D . Now we've learned fortunately about | |
35:39 | the distance formula . We know how to calculate points | |
35:42 | between distances between any points in space . Right ? | |
35:45 | So what is the distance FP Well we have to | |
35:48 | use the distance formula . We know this is X | |
35:50 | comma Y and this is three comma zero . So | |
35:52 | let's do the distance formula . It's gonna be the | |
35:55 | difference in the X values . So we're gonna go | |
35:57 | X -3 Quantity squared plus the difference in the y | |
36:02 | values , Y zero quantity squared square root of this | |
36:07 | . This is nothing more than the distance formula . | |
36:09 | It's calculating the distance between f the focus and this | |
36:13 | particular point right here . I don't know what the | |
36:16 | coordinates are . I'm trying I'm going to create an | |
36:18 | equation to figure out what these coordinates are . That's | |
36:20 | what I'm trying to do but I don't know what | |
36:21 | they are now . So I just take it as | |
36:23 | X comma Y difference in the X value squared difference | |
36:26 | in the lives value squared square with the whole thing | |
36:29 | . This is the distance here . But I know | |
36:31 | that this distance has to be the same as this | |
36:33 | distance so I have to put an equal sign and | |
36:36 | I'm gonna now calculate the distance between these two points | |
36:39 | . Again . The difference of the X coordinates is | |
36:41 | x minus x squared . Notice the x coordinates of | |
36:44 | the same and then the distance the difference in the | |
36:46 | y coordinates is Why -4 Quantity Squared ? It is | |
36:53 | crucial that you understand this equation on the board because | |
36:56 | what's going to happen is we're just going to spend | |
36:58 | the rest of this time simplifying it and then it's | |
37:01 | going to end up showing us that this equation of | |
37:02 | a parabola is correct . Okay , So , what | |
37:05 | we have here is the distance between F and P | |
37:08 | . Just the distance formula . The the distance between | |
37:11 | P and D . This is just the distance formula | |
37:14 | . All right . All right . So , let's | |
37:16 | crank through this . Now , we know that x | |
37:18 | minus X is gonna give us zero squared . We | |
37:20 | know that y minus zero is easy as well . | |
37:22 | So , we're just gonna rewrite this X minus three | |
37:24 | quantity squared plus y squared . Because the zero doesn't | |
37:27 | matter . We still have a square root , This | |
37:30 | is just zero squared , it disappears . So you're | |
37:33 | just gonna have Y -4 quantity squared ? We're gonna | |
37:36 | have square root of this whole thing . All right | |
37:39 | . So all we did was simplify this . Now | |
37:41 | , how do we go any farther ? We have | |
37:43 | a square right on the left and a square root | |
37:45 | on the right . So we're just gonna take and | |
37:47 | we're gonna square the left of this equation . And | |
37:51 | when we do that , then we also have to | |
37:53 | square the right hand side of the equation . This | |
37:56 | square is going to cancel with the square root . | |
37:58 | This square is going to cancel with the square root | |
38:01 | . And so what I'm gonna have after I do | |
38:03 | that is just what's underneath X minus three quantity squared | |
38:08 | plus y squared is why minus four quantity squared . | |
38:15 | And so now you can see I'm not quite there | |
38:16 | , but I'm getting it closer to what an equation | |
38:19 | of a problem might look like . So when you | |
38:21 | look at the actual answer , you see the y | |
38:23 | values on the left and the X values are on | |
38:25 | the right . So let's take all the Y values | |
38:28 | and moving to the left and all the X values | |
38:30 | and moving to the right . And so what we're | |
38:32 | gonna have is when I do that is I'll have | |
38:35 | y squared minus why minus four , quantity squared is | |
38:40 | equal to negative x minus three quantity square . Make | |
38:42 | sure you understand I'm holding this the same , I'm | |
38:45 | subtracting this to get it to this side and I'm | |
38:47 | subtracting this to get it to the right side . | |
38:49 | So that's why there's negative in each location . But | |
38:52 | I have all of the wise on the left and | |
38:54 | all of the X . Is on the right . | |
38:57 | All right . So um notice the right hand side | |
39:01 | of this equation is x minus three quantity squared . | |
39:04 | That's what a problem should have X minus something quantity | |
39:07 | squared and there should be a number out in front | |
39:09 | . In this case the number right now is negative | |
39:11 | one . So actually the right hand side looks good | |
39:13 | , the left hand side doesn't look good , it's | |
39:15 | got too many squares and other things going on . | |
39:18 | So what we have to do is expand this . | |
39:20 | So the way you're going to do that is why | |
39:22 | squared minus . And then what you're gonna have is | |
39:25 | why minus four times why minus four . So we're | |
39:28 | gonna use the binomial squaring stuff that we've done in | |
39:31 | the past . We're gonna take the first thing squared | |
39:33 | , Y squared minus two times Why times four plus | |
39:38 | four times four is 16 . Yes . And so | |
39:43 | we just squared this And then on the right hand | |
39:45 | side we have a negative X -3 quantity squared . | |
39:49 | Okay let me just catch up , make sure I'm | |
39:51 | correct . So then we're going to simplify further , | |
39:55 | we're gonna say well what we're going to have is | |
39:57 | y squared this negative is gonna multiply in making this | |
40:00 | negative Y squared . This negative multiplies in making it | |
40:04 | positive but this is two times y times four . | |
40:06 | So it's gonna be eight , Y negative times negative | |
40:09 | positive . Then we have negative times this gives me | |
40:11 | negative 16 and then this is x minus three quantity | |
40:16 | squared like this now notice we have y squared minus | |
40:21 | y squared , this goes to zero that disappears . | |
40:24 | And then on the left we have uh eight y | |
40:28 | minus 16 . What we wanna do is factor out | |
40:30 | the eight because we have an eight and 16 here | |
40:32 | . So let's factor out the eight . And you | |
40:34 | have y minus two on the left because eight times | |
40:36 | two is the 16 on the right hand side . | |
40:39 | You'll have negative x minus three quantity squared . And | |
40:43 | then let's divide by the eight . So we're gonna | |
40:46 | be left with y minus two is equal to negative | |
40:49 | 1/8 . Because I'm gonna divide both sides by eight | |
40:53 | x minus three quantity squared . Now look at what | |
40:56 | we have done , all we did was draw a | |
40:58 | picture and we said the distance from any point on | |
41:01 | this path , which we're calling p to the focus | |
41:03 | is the same thing as this point . The distance | |
41:06 | from the point to the directorate's , we did the | |
41:08 | distance formulas and then all the rest of it was | |
41:10 | just simplifying . And we end up with this , | |
41:12 | this looks like the equation of a parabola . Why | |
41:15 | minus two is negative 1/8 x minus three quantity squared | |
41:20 | . The example we gave here is in the same | |
41:21 | form why minus something is a constant times X minus | |
41:24 | something quantity squared . In this case we have the | |
41:27 | constant in front that's negative . And so that's why | |
41:31 | it opens upside down . We have a shift that's | |
41:34 | uh 23 units to the right . The vertex will | |
41:37 | be three units to the right . And um and | |
41:40 | uh two units up , so three units to the | |
41:43 | right to units up , three units to the right | |
41:45 | to units up . That's where the vertex is . | |
41:47 | Of this thing . It opens upside down , this | |
41:49 | is the equation of this parabola . So from this | |
41:52 | you can generalize and you can say you can say | |
41:57 | that in general the form is of why minus K | |
42:00 | is a X minus H quantity squared . So what | |
42:05 | we have done is we figured out from the geometric | |
42:08 | definition of what a parabola is , the set of | |
42:10 | all points and equal distance to the focus as it | |
42:12 | is to the directory X . But we've used the | |
42:16 | distance formula to basically make an equation to find out | |
42:19 | that all parabolas have this form . The vertex will | |
42:21 | be shifted according to these X and Y numbers here | |
42:25 | and then the A in the front is going to | |
42:27 | represent how open or close it is . And also | |
42:30 | if it opens up or down . So let's just | |
42:32 | take a second to take a look at what we | |
42:34 | have here and compare it to what we have over | |
42:39 | here . We said the equation of a problem that | |
42:41 | opens up like this looks like this . That's exactly | |
42:44 | what we've written down based on that example . The | |
42:46 | vertex is that h comma K . That's the shift | |
42:49 | in X . The shift and why that's why the | |
42:51 | vertex is H comma K . The focus has to | |
42:55 | be the same distance over in in terms of where | |
42:58 | the vertex is . So the first coordinate has to | |
43:01 | be a church because the vertex is here . So | |
43:03 | for the focus it has to be a church . | |
43:05 | But the y coordinate of the focus has to be | |
43:07 | whatever K is plus this number C . Right ? | |
43:12 | So it's not so helpful to to see it written | |
43:15 | like this , but that's why it's written like this | |
43:17 | . The vertex is hk the focus is H K | |
43:19 | plus C because it's this point plus C units up | |
43:23 | . And why ? That's all it is . The | |
43:25 | axis of symmetry is that X is equal to h | |
43:28 | . It's a vertical line that goes through the focusing | |
43:30 | through the vertex . That's why the axis of symmetry | |
43:33 | is the vertical line X is equal to h this | |
43:36 | coordinate right here . And then the director X is | |
43:39 | the line over here , but it's horizontal line . | |
43:41 | So it has Y equals something . What is going | |
43:44 | to be equal to ? Well , it's gonna equal | |
43:46 | to wherever the vertex is . But because of the | |
43:49 | horizontal line , why is equal to K would go | |
43:51 | right through the vertex . But it's not that line | |
43:54 | , it's k minus C . It's shifted down . | |
43:56 | So the directory is wherever the vertex is a horizontal | |
44:00 | line of wherever the vertex has shifted down , the | |
44:03 | focus is the point , wherever the vertex is shifted | |
44:05 | up , the axis of cemetery goes vertical through both | |
44:10 | of these points there . And then if A is | |
44:12 | greater than zero , it opens up and if A | |
44:13 | is less than zero it opens down . It's a | |
44:16 | monster right to to derive it all and cram it | |
44:19 | all into one lesson . But now you know where | |
44:21 | everything comes from with a practical example . Now I | |
44:25 | would love to be able to stop here and just | |
44:28 | say go do all of your problems . However , | |
44:31 | every class is going to give you problems that has | |
44:35 | a sideways parabola as well and that's honestly it's just | |
44:39 | not fun to have to do it all in one | |
44:41 | lesson but I need to get that out to you | |
44:43 | as well . So what we're gonna do is we're | |
44:46 | gonna do the same thing that we did before . | |
44:48 | We're gonna derive this equation , which is going to | |
44:51 | be very easy to do . Now , you know | |
44:52 | how we did the first one ? And we're gonna | |
44:54 | find out that the equation of a sideways parabola is | |
44:57 | this one , and we're gonna talk about how the | |
44:59 | vertex and the focus and all that stuff makes sense | |
45:01 | there as well . So in order to do that | |
45:05 | , I have to draw like I did here , | |
45:07 | I had to draw a picture of a parabola and | |
45:09 | I had to do the calculations . Now we have | |
45:10 | to draw another picture of a parabola . Uh and | |
45:13 | do the calculations on that one as well . So | |
45:17 | what we're going to have to see if I can | |
45:18 | draw this thing right ? So what we're gonna have | |
45:20 | is an X . Y coordinate . It's not going | |
45:23 | to be perfect , I apologize for that in advance | |
45:27 | . So what I wanna do is I want to | |
45:29 | find and this could be some kind of a test | |
45:31 | question . Find the equation of Parabola with focus at | |
45:44 | zero comma negative two and X is equal to three | |
45:49 | as the director X . All right . So what | |
45:55 | we have figured out what the problem tells us is | |
45:57 | find the equation of the problem with the Focus at | |
45:59 | zero comma negative too . So we can write that | |
46:01 | down right away . Zero comma negative two is going | |
46:04 | to be down here . That's going to be the | |
46:06 | focus of this thing . And I could put an | |
46:08 | F there to tell you that that's the focus . | |
46:10 | Uh Zero negative two . X is equal to three | |
46:13 | is the directory . So here's one , here's to | |
46:15 | here's three . So I'll put a it's X is | |
46:17 | equal to three means it's a vertical line . So | |
46:22 | this is X . Is equal to three . This | |
46:23 | is the Director X . Okay . So because this | |
46:29 | thing has a focus here and the directorate's here , | |
46:32 | you know , the parabola has to open to the | |
46:34 | left because the focus has to be inside the bowl | |
46:37 | , so to speak . And it also has to | |
46:39 | be where the backstop , so to speak . The | |
46:42 | directorate's is in line on the other side of the | |
46:44 | rear end of the problem . So the problem has | |
46:47 | to go something like this . But also we've learned | |
46:49 | many times over . Mhm . That the vertex is | |
46:52 | always halfway between the focus and the directory X . | |
46:56 | So in this problem we actually know what the focus | |
46:59 | is and we know what the directorate's is . And | |
47:01 | so we know there's three points here . So this | |
47:04 | down here , this point right there . In between | |
47:07 | these tick marks , down there has to be the | |
47:09 | vertex . So I'm gonna put here this is the | |
47:12 | vertex . And what is the coordinates of that vertex | |
47:15 | ? It has to be 123 units , but I | |
47:17 | have to cut it in half . So the vertex | |
47:19 | is at three halves comma negative to , the vertex | |
47:23 | is at three halves comma negative too because it has | |
47:25 | to be in between the focus and the directorate's right | |
47:28 | now , what does this problem look like ? I | |
47:29 | always mess these things up so I'm gonna just ask | |
47:33 | you to accept my apologies you know already , but | |
47:36 | it has to go something like this and it has | |
47:38 | to go through the vertex so it's going to do | |
47:40 | something kind of like this is gonna go down , | |
47:42 | it's gonna flat now , it's gonna come out like | |
47:44 | this is the perfect No , I think I drew | |
47:45 | it more where the the vertex is more like here | |
47:48 | , you have to use your imagination and pretend that | |
47:51 | I'm a good artist and I'm not a good artist | |
47:53 | . So sorry about that . So it's gonna be | |
47:54 | something kind of like this that's two kinked . But | |
47:57 | anyway , you see the vertex is right there at | |
47:59 | the lowest point . The thing opens up like that | |
48:02 | . Now the definition says that every point on this | |
48:05 | purple curve is an equal distance to the focus as | |
48:10 | it is to the director . So for instance , | |
48:11 | down here is a point on the curve . We | |
48:13 | can call this point P . X , comma Y | |
48:17 | . Right . And what this is basically saying is | |
48:20 | that like I messed up my little curve here . | |
48:22 | Sorry about that . What this is basically saying is | |
48:25 | that the distance from this point on the parable to | |
48:27 | the focus is the same as this distance from the | |
48:30 | point to the directory . So I'm gonna put a | |
48:32 | little a little lie a little tick mark line . | |
48:35 | This means that's the same distance as this guy and | |
48:38 | that holds for every other point on here . I | |
48:40 | can draw additional points if you want . I can | |
48:42 | pick a point up here and say , well , | |
48:43 | this point right here is an equal distance to the | |
48:46 | focus as this point is to the directorate's those are | |
48:49 | equal distances . And this purple curve traces out all | |
48:52 | possible values of this thing we call the Parabola , | |
48:56 | then every point on here is an equal distance to | |
48:59 | the focus as it is to the director . It's | |
49:00 | that's what it means to be a parabola . All | |
49:05 | right . And so we're gonna do like we did | |
49:06 | in the last problem or we basically said , well | |
49:09 | the distances have to be equal . So we're gonna | |
49:11 | set the exact same thing up and we're going to | |
49:14 | say that if this is a p p m , | |
49:17 | p X . Y . And this is F . | |
49:18 | And this is the point of the directorates . In | |
49:21 | this case if it's down here it's going to be | |
49:24 | , this point's gonna be d . It's gonna be | |
49:26 | at three comma . Why ? Why three comma ? | |
49:29 | Why ? Because the directory is at 123 ? That's | |
49:32 | the X coordinate at this point right here . The | |
49:34 | Y value . I don't know because it depends on | |
49:36 | basically wherever I'm tracing out , whatever point I pick | |
49:39 | is gonna dictate the Y value . But the X | |
49:41 | value is always gonna be the same because the directory | |
49:44 | is always a vertical line at X . Is equal | |
49:46 | to three . So what we're saying is that the | |
49:49 | focus to the point P . Is the same distance | |
49:53 | as the point P . To the directorate , same | |
49:55 | equation that we use before . So we have to | |
49:57 | use the distance formula . I'm gonna have to scooch | |
50:00 | down a little bit to make sure I have room | |
50:03 | . What is the distance between the point F and | |
50:06 | the point P . Well , the point F . | |
50:09 | Was given in the problem statement . The focus was | |
50:11 | at zero comma negative too . So what we're going | |
50:15 | to find is the distance between FP . So let's | |
50:18 | go and take the difference in the X values here | |
50:20 | . So it's going to be x minus zero quantity | |
50:23 | squared , X minus zero quantity squared plus the difference | |
50:27 | in the Y values . Why minus a negative too | |
50:30 | , quantity squared ? We have to take the square | |
50:32 | root to find the distance between those points . But | |
50:35 | we're saying that that distance is the same as this | |
50:37 | distance . So we're going to take the difference in | |
50:39 | the X values here , X minus three quantity squared | |
50:43 | plus the difference in the y values which is just | |
50:45 | y minus y quantity squared . And we're gonna have | |
50:49 | a radical on top of both of those things . | |
50:52 | Now let's clean it up a little bit . What | |
50:54 | we're going to have , X zero is just gonna | |
50:56 | be x squared . And then this is gonna be | |
50:58 | y plus two squared . We're still going to have | |
51:03 | a radical on the right hand side . Let me | |
51:06 | switch colors . Is giving a little bit hard to | |
51:08 | see X -3 Quantity squared , this becomes zero , | |
51:12 | there's nothing else there . So we still have the | |
51:15 | square root outside of this guy . Now we have | |
51:19 | this radical on the left and radical on the right | |
51:21 | . So how do we get rid of the radical | |
51:22 | ? Same as before ? We just square the entire | |
51:25 | left hand side of the equation and then we're gonna | |
51:27 | have to square the entire right hand side of the | |
51:29 | equation so there's still an equal sign between here like | |
51:32 | this . And so the square is gonna cancel with | |
51:35 | the radical and this square is gonna cancel what the | |
51:37 | radical . So really all you have is what's left | |
51:39 | underneath , the X squared plus y plus two squared | |
51:43 | is equal to x minus three . It's weird . | |
51:47 | Yeah . All right . So now what we want | |
51:50 | to do is we want to rearrange terms . Now | |
51:52 | in the previous time we did , it was a | |
51:54 | vertically oriented , probably we wanted to put all of | |
51:57 | the Y values on the left and all the X | |
51:59 | values on the right , and now we're gonna do | |
52:01 | it exactly in the opposite way . We want to | |
52:04 | take and move this term over here . In this | |
52:06 | term over here . You'll see why in just a | |
52:08 | second . So what we're going to have is the | |
52:10 | x squared minus what's on the right , X minus | |
52:14 | three quantity squared , We'll take this and we'll move | |
52:17 | it to the right so it's going to be negative | |
52:19 | Y plus two quantity squared like this . So all | |
52:22 | we did was we move this term to the left | |
52:24 | , this term to the right . And so now | |
52:26 | we want to simplify this so so we want to | |
52:29 | expand this term out as we did before . We'll | |
52:31 | have a X squared minus two times X times three | |
52:37 | plus three times three is nine . And then we're | |
52:40 | gonna have negative Y plus two quantity squared . All | |
52:43 | we did was square the spine . Amiel We've done | |
52:45 | that so many times . You should be able to | |
52:47 | do that in your sleep by now . Now we | |
52:50 | have to distribute the negative end . We'll have , | |
52:52 | sorry this is an X square . I forgot to | |
52:54 | write that down . So we'll have an X squared | |
52:56 | minus X squared taking that negative end . This will | |
53:00 | be a positive term two times three is six X | |
53:03 | . And then the negative times the nine is negative | |
53:05 | nine . And on the right will have negative . | |
53:09 | Why ? Plus two Quantity Square ? We don't want | |
53:12 | to expand this right hand side because it's already in | |
53:14 | the form that we want it to be in for | |
53:17 | a parabola . So this gives me zero like this | |
53:21 | . And then I look at this the six x | |
53:23 | minus nine , the six in front . I want | |
53:25 | to factor out of six and you'll see why in | |
53:28 | just a second , let's factor out of six . | |
53:29 | When I do that , it's going to be x | |
53:31 | minus 9/6 uh is equal to negative Y plus two | |
53:37 | quantity squared . If you don't see this , just | |
53:40 | make sure and go backwards six times X six X | |
53:42 | six times this fraction the sixes will cancel . So | |
53:45 | it'll just give you a negative nine . I'm just | |
53:47 | factoring out the six and when you don't have it | |
53:50 | doesn't go in evenly . Sometimes they have to write | |
53:52 | that second thing as a fraction like this . All | |
53:55 | right . So now we're getting very close this coefficient | |
53:58 | in the front , we want to divide by it | |
54:00 | and this 9/6 is also going to be able to | |
54:03 | be written easily as well as uh This 96 is | |
54:08 | the same as 3/2 . We're gonna divide by six | |
54:12 | so it'll be negative 1/6 . Why ? Plus two | |
54:16 | Quantity Squared ? So we have x minus three half | |
54:19 | is equal to negative 1/6 . Y plus two quantity | |
54:22 | square . So is this correct ? Well this is | |
54:28 | similar to the general form of the equation of a | |
54:33 | sideways parabola which is X um minus K . Is | |
54:39 | equal to a y minus h quantity square . So | |
54:43 | you can see what's going on here , right ? | |
54:46 | The parabola that is oriented vertically up and down , | |
54:50 | so to speak , has the Y value on the | |
54:52 | left . But the X term , the x term | |
54:54 | is on the right and that is what is squared | |
54:56 | for the sideways problem . Everything's flipped around . The | |
54:59 | Y term is what's on the right , that's what | |
55:01 | squared and the X term is on the left . | |
55:03 | So it's totally written backwards to a typical equation . | |
55:06 | And that's because you flip the thing sideways . So | |
55:09 | one way to think of a sideways parabola is just | |
55:11 | the same thing as a vertical parabola . With the | |
55:13 | X and Y variables flipped , you can flip them | |
55:16 | around . So if this were y and this were | |
55:17 | X flip it around . That's going to make a | |
55:19 | sideways version of that parabola but it still has a | |
55:22 | coefficient in front . Uh in this case it's negative | |
55:25 | , so because it's negative , it a positive value | |
55:29 | . It open to the right . A negative value | |
55:31 | opens to the left , which is what our drawing | |
55:32 | had . The vertex of the problem . Is that | |
55:35 | why is equal to negative two and X is equal | |
55:38 | to positive three have , so X is equal to | |
55:40 | positive three halves . Why is equal to negative two | |
55:43 | ? That's exactly what we have here . So you | |
55:44 | see the shift and why goes with this , the | |
55:46 | shift and X goes with this . And now that | |
55:49 | we have done that , we can now look at | |
55:52 | the sideways version of the parabola . The equation of | |
55:55 | the problem . It looks exactly like the equation of | |
55:57 | the other vertically oriented parabola . It's just that we | |
56:00 | take the Y . Value and were replaced with X | |
56:02 | . We take the X value and were replaced with | |
56:04 | why ? Okay . The vertex is still at h | |
56:08 | comma K . The X shift goes with the X | |
56:11 | coordinate of the vertex . The Y shift goes with | |
56:13 | the Y coordinate the vertex . So this is the | |
56:15 | vertex right here . The focus has to be this | |
56:17 | point , but plus a little more in the X | |
56:20 | direction . So we have to add , see in | |
56:22 | the X direction , K stays the same . The | |
56:25 | directorate is si units in the other direction . So | |
56:29 | it has to be a vertical line that is uh | |
56:33 | H instead of plus C . It's going to be | |
56:35 | minus E because it's going to be a line that's | |
56:37 | going to be over here . In other words , | |
56:38 | a vertical line that goes right through this point would | |
56:40 | be X is equal to h right through here . | |
56:43 | But we don't want that line . We want it | |
56:44 | to be si units this way . So we call | |
56:46 | it h minus C . Okay . The axis of | |
56:50 | symmetry for horizontal kind of problems like this is a | |
56:54 | horizontal line , right ? Because it can't be a | |
56:57 | vertical line that goes with vertically oriented parabolas , horizontal | |
57:00 | parabolas have to have a horizontal line and it goes | |
57:03 | through the point K . Why is equal to K | |
57:05 | . Because it goes right through the vertex . And | |
57:07 | then of course when A . Is bigger than zero | |
57:09 | , it opens toward the positive X . Values when | |
57:12 | a . Is less than zero opens towards the other | |
57:14 | direction opposite of that . We have done a tremendous | |
57:17 | amount of this lesson . And to be honest with | |
57:19 | you , I don't like filming lessons this long but | |
57:22 | I had to in this case because if I just | |
57:24 | give you the equations , you won't understand what to | |
57:26 | do with them . And if I just derive the | |
57:29 | shape of the proble you won't know how to solve | |
57:31 | any problems . And if I just review stuff like | |
57:33 | we did in the beginning , then you'll just review | |
57:36 | what we've learned and you won't go any farther . | |
57:38 | So in this lesson we have gone from where we | |
57:43 | have started . We know that problems have this equation | |
57:45 | , we knew that , but then we talked about | |
57:47 | the focus of a problem . We talked about the | |
57:49 | definition being that these points on the parabola are an | |
57:51 | equal distance to the focus as they are to this | |
57:54 | line called the directorate's , which by the way , | |
57:56 | the bottom part of the problem is always in the | |
57:58 | middle of the focus and the director is always that's | |
58:02 | very useful for you to know that's the definition of | |
58:04 | actually it's halfway right there . Then we apply that | |
58:07 | definition and we say , well , if this distance | |
58:09 | has to be the same as this distance , will | |
58:11 | calculate the distances will set them equal . The rest | |
58:14 | is just algebra . And you get it down to | |
58:15 | the equation of the problem that we have used . | |
58:17 | Why minus some shift on the left , X minus | |
58:20 | some shift on the right squared . This determines if | |
58:23 | it opens up or down . Then we do the | |
58:25 | exact same thing horizontally . We say let's draw horizontal | |
58:29 | problem here is the vertex , right in the middle | |
58:31 | , between the focus and the directorate's , this distance | |
58:33 | has to be the same as this distance will set | |
58:35 | this distance equal to the other distance . We'll do | |
58:38 | all the algebra to get it all down . But | |
58:39 | what we find is that the roles of X and | |
58:42 | Y are flipped . It was why ? On the | |
58:44 | left and X squared on the right now it's X | |
58:46 | on the left with y squared on the right . | |
58:49 | So this would be the general form of the horizontal | |
58:51 | parabola . The shift and Y . For the vertex | |
58:54 | goes here , the shift and X for the vertex | |
58:56 | goes here . Those rules still apply the number in | |
58:59 | front determines if it opens to the right or to | |
59:02 | the left , just as you would expect towards positive | |
59:04 | extra towards negative X . And then finally we have | |
59:07 | this which we're gonna use for all of our problems | |
59:11 | . Every problem has a vertex focus and directorates . | |
59:15 | The equation of the problem is here , the vertex | |
59:17 | focus access the cemetery and directorates . We've all talked | |
59:20 | about them and then we have this other relation A | |
59:23 | . Is equal to the distance . The focus is | |
59:26 | 1/4 times that distance A is 1/4 C . That | |
59:29 | is not something I derive for you in this lesson | |
59:32 | . It's something that's usually just given to you . | |
59:34 | I could derive it but it's it's not really worth | |
59:36 | our time . You just need to use this equation | |
59:38 | quite a bit because it relates the parameter A to | |
59:41 | where the focus is located . C units away . | |
59:44 | You have the same relation down here , a similar | |
59:46 | relations for the vertex focus and axis of symmetry and | |
59:49 | so on . I know it looks complicated now , | |
59:52 | but when we sit down and do our problems , | |
59:54 | these problems will not be difficult . But you have | |
59:56 | to know that every parabola has a vertex , has | |
59:59 | a focus , has a line called the directorate's what | |
60:02 | the definition of a parabola is and so on . | |
60:04 | And now that , you know all of those things | |
60:06 | , you can conquer any problem I throw at you | |
60:08 | in terms of parabolas . So follow me on to | |
60:10 | the next section . We're going to do that right | |
60:12 | now . |
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