12 - What are Inverse Functions? (Part 1) - Find the Inverse of a Function & Graph - By Math and Science
Transcript
00:00 | Hello . Welcome back . The title of this lesson | |
00:02 | is called inverse functions . This is part one of | |
00:05 | several . So here's a concept that gives a lot | |
00:08 | of students a lot of problems . And even when | |
00:10 | you think you understand it , there are usually a | |
00:13 | few little aspects that you really ever either didn't think | |
00:15 | about or really just didn't understand . To begin with | |
00:17 | . What I want to do is make sure you | |
00:19 | understand by the end of this lesson what an inverse | |
00:21 | function is , what the graph of an inverse function | |
00:24 | really looks like , but mostly just intuitively to know | |
00:27 | what an inverse is and why it's important in math | |
00:30 | . All right . So let me let you take | |
00:32 | a trip down memory lane with me , just for | |
00:34 | a second , we know that we understand how to | |
00:37 | solve equations . Generally in order to solve an equation | |
00:40 | for X , we have to kind of undo everything | |
00:43 | that's happening to X to put X by itself on | |
00:46 | one side of the equal sign . If something is | |
00:48 | added to one side , and then we have going | |
00:49 | to subtract to get X by itself , if something | |
00:52 | is multiplied by X . And we usually divide , | |
00:54 | we do the opposite . Up until now we've been | |
00:57 | saying that we've been doing the opposite to undo the | |
01:00 | operations to get X by itself . Really , we're | |
01:02 | going to dive a little bit more into that . | |
01:04 | And we're going to talk about the idea that you've | |
01:06 | already been kind of using inverse is up until now | |
01:09 | the additive inverse you've been using , that's what we | |
01:11 | call to undo addition and the multiplication , or the | |
01:15 | multiplying inverse . That's what we do to undo multiplication | |
01:18 | . So we've already been doing that , but now | |
01:19 | we're putting different words , were calling them in verses | |
01:22 | , right ? But then we're going to extend that | |
01:24 | concept to functions , functions can have inverse is also | |
01:28 | and that's where the wheels come off the train a | |
01:31 | little bit for a lot of students , because they | |
01:33 | don't they can kind of understand what it is , | |
01:34 | but they have no idea why we're doing it . | |
01:36 | The reason that we're doing it is because later down | |
01:38 | the road , when we solve more complicated equations in | |
01:41 | order to get X by itself , when we're solving | |
01:43 | equations , we're going to do the opposite , do | |
01:46 | the undo the undo operation . In other words , | |
01:49 | we'll apply the inverse function in order to get X | |
01:52 | by itself to solve more complicated equations . Right now | |
01:55 | you've been doing in verses a lot , even subtracting | |
01:57 | and multiplying or dividing whatever . But later down the | |
02:00 | road , especially with exponential functions , we're going to | |
02:03 | have to do a inverse function to get X by | |
02:05 | itself . And so now we have to learn what | |
02:07 | it in verses . And then we're gonna apply that | |
02:09 | as we start to to learn what the inverse of | |
02:11 | the exponential function is . And by the way , | |
02:13 | it's called a logarithms . We're gonna talk about logarithms | |
02:16 | . So this is very important to understand what the | |
02:18 | algorithm is . So , first let's go down and | |
02:21 | make sure you understand what some of these other things | |
02:24 | are . So we have the concept of the additive | |
02:28 | in verse . And believe me , I know a | |
02:32 | lot of people probably want to skip through this because | |
02:34 | they know what addition is . But just trust me | |
02:36 | , go through it with me because the conclusions I'm | |
02:39 | going to draw about additive inverse is directly related to | |
02:42 | what an inverse function is . So , it's very | |
02:44 | important that you follow me through this . So let's | |
02:48 | say you start with a number any number you want | |
02:50 | ? I'm gonna pick a number 14 , that seems | |
02:52 | like a nice number . All right . And I'm | |
02:54 | going to add something to it . So , I'm | |
02:55 | gonna change this number . I'm gonna add , you | |
02:57 | know , let's change colors . I'm gonna add something | |
02:59 | to 14 and change that number . I'm going to | |
03:02 | add five to it . So now if I were | |
03:04 | to add that together , that would be 19 . | |
03:06 | But let's say I want to undo this , I | |
03:08 | want to change it back into 14 . Well , | |
03:10 | I have to do the opposite of the addition that | |
03:12 | I did here , which would be subtraction of the | |
03:15 | same number five . And what I would get out | |
03:17 | as a result of that would be 14 . Exactly | |
03:20 | what I started with . Okay , you might say | |
03:23 | this is pretty simple and pretty dumb . Why is | |
03:25 | he teaching me this ? What I'm trying to say | |
03:27 | here is the additive in verse of The # five | |
03:37 | is the number -5 . Now , you see that | |
03:40 | symmetry of the number line . The positive numbers and | |
03:43 | the negative numbers . The negative numbers are the additive | |
03:44 | inverse is of the positive numbers . You probably saw | |
03:47 | this definition way back in Algebra one , but you | |
03:50 | don't care back then because who cares ? They're additive | |
03:53 | inverse . Great . What you've done here is you | |
03:55 | take a number , You change it by adding something | |
03:57 | to it . You have to do the inverse to | |
03:59 | undo that to get back what you started with . | |
04:02 | I want you to remember this concept of getting back | |
04:04 | what you started with because this concept of getting back | |
04:07 | what you started with is exactly how we're going to | |
04:09 | tackle inverse functions here in just a second . All | |
04:12 | right . So , as another example , let's say | |
04:15 | you start with 20 the number 20 . I'm just | |
04:17 | making this number up . And let's say you subtract | |
04:20 | six from 20 but then you want to undo that | |
04:22 | . How do you wanna do that ? Where you | |
04:23 | have to add six back ? What do you get | |
04:25 | back As a result 20 ? You start with something | |
04:28 | , you do something to it , you immediately undo | |
04:30 | it and you get back exactly what you started with | |
04:32 | . Right ? And so you can say here that | |
04:36 | um the additive in verse of negative six is Positive | |
04:45 | six . Okay , so we talked about additive inverse | |
04:48 | is awesome . How do we apply that ? Well | |
04:51 | , let's talk about something related to that . Let's | |
04:53 | talk about the multiplication in verse . It's a really | |
05:01 | similar concept . It's not any harder at all . | |
05:04 | All right . Let's pick a number out of thin | |
05:06 | air . Can be any number I want . Let's | |
05:07 | pick 16 . And let's say I multiply 16 by | |
05:11 | something . Let's say I multiply it by four , | |
05:13 | but I want to get back 16 . So , | |
05:15 | how do I undo this multiplication ? I can't add | |
05:17 | or subtract the negative four . That's not going to | |
05:19 | undo that because this is multiplication . How do I | |
05:22 | get the 16 back ? Well , I'm gonna have | |
05:24 | to multiply by 1/4 Right ? And that's gonna give | |
05:28 | me 16 . So you see by multiplying by four | |
05:31 | , I've changed the original number , but I can | |
05:33 | immediately undo that by multiplying by the inverse of Ford | |
05:36 | . But not the additive inverse . It's the multiplication | |
05:39 | inverse . So what it's telling you is that the | |
05:42 | inverse of multiplication is division because you're multiplying something . | |
05:45 | But what you're multiplying by is division . So the | |
05:47 | inverse of multiplication division . The inverse of addition is | |
05:51 | subtraction . Is exactly what I said in words at | |
05:53 | the very beginning of this lesson . The goal is | |
05:56 | if you start with something , you multiply by something | |
05:58 | , you multiply by the inverse to undo that you | |
06:00 | get back . What you started with . We get | |
06:02 | back what we started with we get back what we | |
06:04 | started with . That's what I want you to remember | |
06:05 | all throughout this lesson . Because inverse functions are all | |
06:09 | about how to get back what you started with . | |
06:11 | So we say That this multiplication in verse 1/4 . | |
06:15 | We say that it un does it um does it's | |
06:18 | not a technical word , that's my word button does | |
06:20 | the multiplication by the four . So they kind of | |
06:22 | annihilate each other and you end up with what you | |
06:24 | basically started with . So now we're gonna move the | |
06:27 | train along a little bit and talk about inverse functions | |
06:30 | . Because that's where again students start to get , | |
06:32 | they have no idea why we're doing this or anything | |
06:34 | . But basically what happens is an inverse function is | |
06:37 | what we want to kind of undo what the first | |
06:40 | function does . It's like the opposite function . Think | |
06:42 | of peanut butter and jelly , or mayonnaise , and | |
06:45 | mustard , or ketchup , and mustard . Whatever you | |
06:47 | have these little pairs of things that go together . | |
06:48 | Every function I shouldn't say every function . Every function | |
06:51 | that we will talk . We'll talk about how to | |
06:54 | figure out if the function has its inverse . But | |
06:56 | most functions have a cousin function called an inverse function | |
07:00 | that essentially un does what the original function is doing | |
07:04 | . And so mathematically , that means it's going to | |
07:06 | literally take an undo the mathematical machinery of that first | |
07:10 | function with the inverse function mechanic . So , let's | |
07:14 | take a concrete example . All right , let's see | |
07:18 | how much space do I have ? I don't want | |
07:19 | to save some room . Let's say I have a | |
07:21 | function F of X . And it's equal to X | |
07:25 | plus four . Over to This is a really simple | |
07:28 | function . And let's say I have another function G | |
07:30 | . Of X and it's equal to two x minus | |
07:34 | four . Now , I'm gonna give you the punch | |
07:36 | line , these are inverse functions of one another . | |
07:38 | You cannot tell by looking at them that their inverse | |
07:41 | . So just forget it , especially if I give | |
07:42 | you more complex function , you'll never be able to | |
07:44 | look at it and just say , oh yeah , | |
07:46 | those are inverse function . You're never gonna be able | |
07:47 | to do that . I'll show you how to be | |
07:49 | able to tell what their inverse functions , but I'll | |
07:51 | tell you ahead of time these are inverse functions . | |
07:53 | So they're special . They go together right there very | |
07:56 | uh they have a lot of synergy between them , | |
07:58 | you could say , right , let's take a look | |
08:00 | at what that might look like , what that synergy | |
08:02 | is . Let's take and look at the following thing | |
08:06 | . Yeah , let's look at G . Of one | |
08:11 | . This is the function G let's put the number | |
08:12 | one into their , what would we get ? We | |
08:14 | put the number one into their , this is the | |
08:16 | input , right ? We put the input into here | |
08:18 | . What do we get ? two times 1 -4 | |
08:21 | . That's what we get . So then when we | |
08:23 | calculate that we're gonna get to then minus four , | |
08:26 | we'll get negative to . So G F one is | |
08:28 | equal to negative two . Now , just like we | |
08:32 | learned in the last section with composite functions , you | |
08:34 | can change these functions together or nest them however you | |
08:37 | want to think about it . We talked about composite | |
08:39 | functions in the last lesson . If you haven't done | |
08:41 | that , you have to know that to get this | |
08:43 | . So let's take the output of this function uh | |
08:46 | here . And let's run it through the other function | |
08:48 | which you know ahead of time . It's an inverse | |
08:50 | function . So let's see what happens . Take this | |
08:52 | guy and let's run it through the F . Function | |
08:54 | , which is the cousin function of that guy . | |
08:56 | And what we get is F . Of G . | |
08:58 | Of one , which means we've done this . So | |
09:01 | then we say , let's run the number negative two | |
09:04 | in through the F function , because that's what we | |
09:06 | got is an output . We stick it into the | |
09:09 | outermost function here . Okay , What do we get | |
09:11 | ? Take this over here . What we're going to | |
09:13 | get is what I want to do it . Let's | |
09:16 | do it right here . It's gonna be negative two | |
09:18 | plus four over to just take it and stick it | |
09:21 | into here . What do we get here ? Negative | |
09:22 | two plus four is going to be 2/2 . So | |
09:26 | what we get is one , so F of G | |
09:29 | . Of one Is equal to one . I want | |
09:33 | to make sure you understand what's happened here and and | |
09:35 | in fact it's not so obvious at first . But | |
09:38 | look back to what we did in the beginning . | |
09:40 | I said additive inverse . We start with some number | |
09:42 | , we add something to it , but we do | |
09:44 | the inverse and we get back what we started , | |
09:46 | we start with a number , we subtract something , | |
09:48 | we do the inverse . We get the number back | |
09:50 | . The inverse gives you back what you started with | |
09:52 | it and does the thing that you've done to it | |
09:54 | . So here we multiply by four . We do | |
09:55 | the universe and we get back where we started here | |
09:58 | . We know that these are inverse functions because I'm | |
10:01 | telling you they are . If you put the number | |
10:02 | one in here , we get this out . But | |
10:04 | if we take and run that through the other function | |
10:06 | , we get the number one out . We put | |
10:09 | a one in and we get on one out . | |
10:11 | That's exactly what we did there . We start with | |
10:13 | a number , we do something , we do the | |
10:15 | universe and we get what we started with . We | |
10:17 | start with the number we do a function , we | |
10:19 | do its inverse and we get the number out inverse | |
10:22 | functions undo each other . I'll say it again . | |
10:26 | Inverse functions undo each other . I'll say it a | |
10:29 | third time . An inverse function un does what the | |
10:32 | other function does . That's what they are there special | |
10:34 | functions . These are not random functions off , you | |
10:37 | know , just randomly taken their specially crafted to be | |
10:40 | in verses of one another . Right ? So let's | |
10:44 | spell this out a little bit more . Okay , | |
10:47 | I'll say note , what do we do here ? | |
10:50 | G . Of one . That's what we started with | |
10:52 | . We calculated that we got an answer of negative | |
10:55 | two . But then we ran that function through or | |
10:59 | the answer through the other inverse function which is F | |
11:04 | . And we got an answer of one out . | |
11:06 | We started the chain by putting a one in . | |
11:08 | We went through this calculation intermediate value than running it | |
11:12 | through the inverse . And we get a number out | |
11:13 | that's exactly equal to what we started with . So | |
11:16 | these are the same . These are the same . | |
11:21 | Now I want to go off to the side here | |
11:25 | and show you something . We ran . We did | |
11:29 | uh F . Of G . Of one . Now | |
11:31 | let's go over here to the side . And this | |
11:33 | calculate something similar instead of F . Of G . | |
11:35 | Of one . Let's calculate G . Of F . | |
11:40 | Of one . So this is a composite function . | |
11:44 | We gotta one . We're gonna do the composite function | |
11:46 | again . But we're gonna flip it around . And | |
11:48 | if you remember I told you in the last lesson | |
11:50 | when we did composite functions , I said in general | |
11:52 | when you flip the order of the composite function , | |
11:54 | you do not get the same thing . But there's | |
11:57 | a big exception and the big exception are inverse functions | |
12:00 | , inverse functions always undo each other no matter what | |
12:04 | order you do them , that's why they're special . | |
12:06 | So here we did F . Of G . Of | |
12:07 | one here . Let's do G . Of F . | |
12:09 | Of one . So how do we do that ? | |
12:12 | Well we say , well f . of one is | |
12:15 | this it's going to be one plus 4/2 Which is | |
12:19 | 5/2 . It's an ugly fraction . But let's take | |
12:23 | that ugly fraction and we're gonna put it into here | |
12:25 | . So g . of f . of one means | |
12:28 | that what we do have a five halves here . | |
12:30 | So we do G . Of five halves because that's | |
12:33 | what we calculated . We're feeding that into the G | |
12:35 | function . What is the G function ? It's this | |
12:38 | it's two times the input here , which is five | |
12:42 | halves minus four . So I've taken this and I'm | |
12:45 | sticking it into the G function . But notice the | |
12:48 | two's cancel . So what you get is G . | |
12:50 | Of F . Of one is the two's cancel . | |
12:54 | So you have just a five left over minus four | |
12:56 | so G of F . Of one . It's just | |
12:59 | equal to one . And notice what happens . Is | |
13:03 | that this is the same thing . Mhm . All | |
13:09 | right . That's the that's one of the major conclusions | |
13:12 | I want you to remember from this . I told | |
13:14 | you a great paint in great detail in the last | |
13:16 | lesson . When you flip the order of the composite | |
13:19 | function , you're not gonna get the same thing . | |
13:20 | But that's for random functions that pull a random function | |
13:23 | F of X . Is X squared , pull another | |
13:25 | random function F of X is two X -3 . | |
13:28 | Okay , those are random . If I do the | |
13:30 | composite functions in both orders , in the different orders | |
13:34 | , I'm gonna get different answers . But inverse functions | |
13:37 | are special . They always undo each other . I | |
13:39 | put the input in of a one . I run | |
13:42 | it through one of the functions . Then I immediately | |
13:44 | run it through the inverse function . Then I get | |
13:46 | the same exact number out . I stick a number | |
13:48 | in here . I run it through the G function | |
13:50 | , I run it through its inverse which is the | |
13:52 | F function . I get exactly the same number out | |
13:54 | which is one . All right . And that's going | |
13:58 | to be the case of all inverse function pairs . | |
14:00 | Alright , So make sure I haven't missed anything so | |
14:02 | far . They undo each other G NF undo each | |
14:05 | other . And you're always going to get that input | |
14:07 | function , that input number back out . So what | |
14:09 | I want to do now is I want to give | |
14:11 | you a few more examples of this whole undoing business | |
14:15 | and then after that I want to um graph the | |
14:19 | inverse function . So let's rewrite these functions here just | |
14:21 | to have them handy . Ffx is X plus 4/2 | |
14:27 | . G . Fx two . X -4 . Same | |
14:32 | functions . I haven't changed anything . I just want | |
14:34 | to have uh everything down low here . Now let's | |
14:37 | do the same thing . Let's say F of negative | |
14:40 | three . Let's put a negative three in here . | |
14:43 | So the negative three plus 4/2 . So we add | |
14:48 | them on the top and we get a one and | |
14:50 | we get so we get a one half out of | |
14:52 | that . So what we figured out is F of | |
14:54 | -3 . This intermediate answer is one half after we | |
14:56 | run it through one of the functions . Let's take | |
14:59 | that and then run it through the other functions . | |
15:01 | So you'll say that G of F of negative three | |
15:06 | Is going to be G of 1/2 is going to | |
15:11 | be equal to , I have to put in one | |
15:12 | half in year two times one half for x -4 | |
15:16 | . The 2s are going to cancel . So what | |
15:19 | I'm going to have here is just the tools are | |
15:20 | gonna cancel . So we're gonna have a 1 -4 | |
15:22 | which is three . Notice the three is exactly what | |
15:26 | I'm sorry ? Not a 3 -3 . One minus | |
15:29 | four is negative three . It's exactly what I started | |
15:31 | with exactly my input here . So G of F | |
15:34 | of negative three is surprised negative three . Because these | |
15:38 | are inverse functions . Whatever number I put in , | |
15:42 | I run it through one of the functions and I | |
15:44 | run it through the other function and then I get | |
15:46 | exactly what I started with . It's exactly like undoing | |
15:48 | each other from before . So just to spell it | |
15:51 | out one more time , I could say , I | |
15:55 | could say uh Let's see here f of -3 Yields | |
16:01 | a value of 1/2 . But then I put that | |
16:04 | through the other function G of one half , and | |
16:07 | that yields a function of . Sorry here . Yeah | |
16:11 | . Do you have one half yields a number of | |
16:13 | negative three ? So I start the chain by putting | |
16:15 | a value of negative three in and I get out | |
16:17 | of the chain or out of the nest . However | |
16:19 | you want to look at it the same exact input | |
16:21 | value . They've undone each other . It turns out | |
16:24 | that this undoing of one another is going to help | |
16:26 | us solve lots of equations down the way that we | |
16:29 | don't know how to solve now . Mostly in the | |
16:31 | beginning , will be solving exponential equations because the exponential | |
16:34 | function has an inverse . I'm going to talk about | |
16:36 | it later . It's called the law algorithm . So | |
16:38 | if you take the law algorithm of both sides of | |
16:40 | the equation , you kind of undo the exponential function | |
16:44 | and then bam the variable drops out because you've kind | |
16:46 | of annihilated and eliminated the exponential part . Because you've | |
16:50 | done it's inverse , you've undone it just like we | |
16:52 | add in order to undo subtraction and we divide two | |
16:56 | under division , we do the inverse , which might | |
16:58 | be taking the law algorithm to undo the exponential function | |
17:01 | here , we don't have any exponential . I'm just | |
17:03 | explaining what these things are , what these inverse functions | |
17:07 | are . All right . So then let's do one | |
17:12 | more just to bring it home here . We have | |
17:16 | said with these two functions , we put a number | |
17:18 | in of one . Run it through both of these | |
17:21 | functions and we get a number one out . We | |
17:23 | reverse the order of the functions . Doesn't matter . | |
17:26 | We still stick a number one in . We get | |
17:27 | a number one out . Let's change the input . | |
17:30 | We put a number negative three and we run it | |
17:31 | through both functions . We get a negative three out | |
17:33 | . Now , let's not put a number in . | |
17:36 | Let's just put a variable in . Let me rewrite | |
17:38 | the functions F of X is equal to X plus | |
17:42 | 4/2 , and G of X Is two X -4 | |
17:50 | . Same functions . Now , instead of putting a | |
17:52 | number in calculating it and putting into another and calculating | |
17:55 | it . Let's just do this . Let's calculate generally | |
17:58 | F of G of X . In other words , | |
18:01 | we're not putting a number and we're leaving the input | |
18:04 | of that innermost function , Just a variable . We're | |
18:07 | letting the input to the whole process be any number | |
18:10 | we want we just call it X . So when | |
18:12 | we put X in two G of X , what | |
18:14 | do we get ? We get this and we have | |
18:15 | to take this thing and put it into the F | |
18:18 | location . So that means we take this whole thing | |
18:20 | and stick it where X is . So it'll be | |
18:22 | two x minus four plus 4/2 . We just took | |
18:27 | G of X , whatever it was and we stick | |
18:29 | it in the X location right there . Now look | |
18:31 | at what you have , you can drop the parentheses | |
18:33 | now two x minus four plus four . Over to | |
18:37 | this is going to go to zero . So you're | |
18:39 | gonna have to X over two which is gonna give | |
18:42 | you once you cancel X notice what's happened , We | |
18:45 | stick a value of X . M Which means any | |
18:47 | value I want . I run it through both functions | |
18:50 | and I get the same exact value back . That's | |
18:52 | exactly what was happening over there . Put a one | |
18:55 | in , get a one out , put a negative | |
18:57 | three in . Get a negative three out . Put | |
18:59 | any value I want in for X . I'd stick | |
19:00 | it exactly the same value of X out . That's | |
19:02 | what that's telling you . When you operate an inverse | |
19:05 | on uh the inverse function on the other function . | |
19:08 | They annihilate each other and you're just left with whatever | |
19:10 | input you had to the whole chain . Yeah . | |
19:14 | All right . Now , just to make sure we're | |
19:16 | on the same page , let's run that same process | |
19:18 | through in reverse instead of F of G of X | |
19:20 | . Let's do G of F of X . Again | |
19:24 | leaving it general we have ffx , we're gonna put | |
19:26 | it inside of G . We have to stick this | |
19:27 | whole thing and put it in there . So to | |
19:30 | be too times X . But this X . Is | |
19:33 | the entire function X plus 4/2 . And then we | |
19:38 | have to uh do this guy now when we have | |
19:41 | a two on the outside and one half here they | |
19:43 | can cancel like this . And so what you're going | |
19:46 | to have is X plus four left over . That's | |
19:49 | all that's left out of this . But then you | |
19:51 | have a minus four and look here , this goes | |
19:53 | to zero . So you get an X out so | |
19:56 | you stick an X in , you run it through | |
19:57 | both functions in reverse order from before and we still | |
20:01 | get exactly the same thing . So what we have | |
20:03 | concluded is that F of G of X is equal | |
20:09 | to X . And we've concluded that G of F | |
20:13 | of X is equal to X . Now , I | |
20:18 | could have started this whole lesson by giving you this | |
20:21 | gibberish here and said , hey , there are these | |
20:23 | things called inverse functions F of G of X . | |
20:26 | X M G of F of X is X . | |
20:28 | Don't you understand ? Nobody's going to understand that . | |
20:31 | I don't even understand that when I say it out | |
20:33 | loud doesn't make any sense . But by going through | |
20:35 | the whole thing , I hope you can understand what | |
20:36 | this means . It's this is what you would typically | |
20:40 | see in most textbooks as the definition of the inverse | |
20:43 | function . And that definition goes like this F and | |
20:49 | G . R in verse functions if the following thing | |
21:00 | , if this is true , right ? So this | |
21:04 | is what I'm gonna circle as the definition of the | |
21:06 | inverse function . So , somewhere in your algebra book | |
21:08 | or pre calculus book or calculus book or whatever , | |
21:11 | they're gonna define this thing called an inverse function . | |
21:13 | They're gonna say F and G are inverse functions . | |
21:15 | If F of G of X , X , N | |
21:18 | G of F of X is X . And then | |
21:20 | probably have some other words about the domain . You | |
21:22 | have to make sure the domain this is true in | |
21:24 | the domain of G and that this is true of | |
21:26 | the domain of F . But assuming both of these | |
21:28 | are smooth continuous functions with no , you know , | |
21:31 | assume taub's infinities or anything , they're very well behaved | |
21:33 | functions , then this is going to be true for | |
21:35 | all X . For all input values of X . | |
21:38 | Whatever input you put in , you're gonna get an | |
21:40 | input , you're gonna get exactly the same number coming | |
21:43 | out of the other end . Once you run them | |
21:44 | through both of these functions , it won't matter the | |
21:47 | order and what you do it . This is the | |
21:49 | definition of an inverse function that you're gonna see in | |
21:51 | most books . But we just went through the process | |
21:53 | here so that you can hopefully understand it a little | |
21:55 | bit more . All right . Now , what I | |
21:57 | want to do is just as important as everything we've | |
22:00 | done up to this point . We want to graph | |
22:02 | these functions . I want to show you what a | |
22:04 | graph of a function looks like right next to what | |
22:07 | the graph of its inverse looks like , because it | |
22:10 | turns out there's a really easy way to visualize what | |
22:13 | an inverse function uh will look like . And it | |
22:16 | helps us understand what they're what they're really doing . | |
22:18 | All right . What an interest functions really doing . | |
22:20 | So , what we wanna do is want to plot | |
22:22 | both of these functions . All right . So , | |
22:25 | we have these two functions here . We have F | |
22:26 | of X is equal to X plus four . Over | |
22:30 | to That was function number one , and G fx | |
22:34 | Is two , X -4 . This is a line | |
22:38 | and this you might not realize it , but it's | |
22:40 | also a line . Let's kind of manipulate this a | |
22:42 | little bit f of X . This can be broken | |
22:46 | up as X over two plus four over to just | |
22:49 | divide each term by two . Of course . This | |
22:51 | is going to be F of X one half times | |
22:55 | X plus two Mx plus B . Mx plus B | |
23:00 | . They're different lines . The Y intercepts are different | |
23:03 | and the slopes are different but they're both lines . | |
23:06 | So you can immediately tell that they're both going to | |
23:08 | do something but they're not gonna have any squiggles and | |
23:11 | they're not gonna have any parameters . Are not gonna | |
23:12 | have anything crazy like a lips or circle or anything | |
23:15 | like that . They're both can look like lines . | |
23:17 | So what I wanna do is I wanna graph this | |
23:19 | f . Function . I want to graph this right | |
23:23 | on the same graph as this guy . So it's | |
23:25 | probably gonna take a little bit of time . But | |
23:27 | I really encourage you to hang on with me because | |
23:29 | it's really important um for us to get there . | |
23:33 | It's very important for us to actually um to do | |
23:37 | that to do this together . So what I want | |
23:39 | to do is , first of all right , the | |
23:40 | functions down again , right ? The first function let | |
23:44 | go and write him up in the upper left hand | |
23:46 | corner here . The first function F . Of X | |
23:50 | . Was one half X plus two . That's what | |
23:52 | we just wrote down . And the other function G | |
23:55 | . Of X . Is two X -4 like this | |
24:00 | . So , those are the two functions we want | |
24:01 | to graph , fortunately they're really easy to graph because | |
24:04 | they're just lines . So what do I want to | |
24:06 | use to graph these guys ? What color ? Let's | |
24:08 | try this one . That's probably not gonna look so | |
24:10 | great . Let's try . Mm We'll try this one | |
24:15 | . Okay , the first one . All right . | |
24:17 | We have for the first one . Why intercept of | |
24:20 | two ? So here's one . Here's two . So | |
24:21 | I'm gonna put a dot right here . It passes | |
24:23 | through this point . But the slope on this one | |
24:26 | is one half X . So that means I rise | |
24:28 | one and I run to okay rise one or 12 | |
24:33 | There's different ways in which you can do it . | |
24:35 | But let's go and do it that way up 1/1 | |
24:38 | , 2 . Because the scale is one tick mark | |
24:41 | and the scales one tick marks all up and then | |
24:43 | over to like this and then I can go uh | |
24:48 | I can do the same thing here . I can | |
24:49 | go Down one and over to like this , something | |
24:54 | like this . Okay , because it's going to be | |
24:57 | up 1/2 , up one over to something like that | |
25:00 | . So I can draw a line smoothly through those | |
25:02 | points . So let's do that real quick and see | |
25:05 | if I can not drop my paper in the process | |
25:07 | here . Try to do the best I can . | |
25:09 | It's not going to be perfect , but let's try | |
25:12 | to get it as close as we can because there | |
25:15 | actually is something really neat that I want you to | |
25:17 | be able to see . Yeah , so it's going | |
25:21 | to look something like this like that . All right | |
25:27 | , let's just double check myself . Okay , so | |
25:29 | this function F of X is equal to the one | |
25:34 | half X plus two . But remember that just came | |
25:36 | from X plus 4/2 . It was the same exact | |
25:39 | thing . So we'll say X plus 4/2 . So | |
25:43 | this is the graph of this function . All right | |
25:47 | . Um Then let's go and grab the other one | |
25:53 | and for that one I think I want to try | |
25:54 | to use let's use black . So two X minus | |
25:58 | four . So we have minus four means a Y | |
26:00 | intercept negative one , negative two negative three negative four | |
26:03 | crosses right there and a slope of two . That | |
26:05 | means up to over one , up to over one | |
26:09 | like this . Up to over one like this . | |
26:12 | So it goes through those three points . Let me | |
26:15 | see if I can graph it through there . Something | |
26:21 | like this . I can get there . It's gonna | |
26:26 | look something like this . Okay , something like that | |
26:36 | . Not perfect . You get the idea now in | |
26:38 | your mind I want you to extend this blue line | |
26:41 | . Of course it goes on and on forever and | |
26:42 | extend the black line that goes on and on forever | |
26:45 | . Now , the interesting thing I want to show | |
26:47 | you is , well , let me go ahead and | |
26:48 | draw , guess write this down . This is um | |
26:52 | f of X is two X -4 . That's what | |
26:56 | that is now . Don't they look interesting ? It | |
26:59 | looks like they're a mirror image of one another . | |
27:02 | One of the functions , its inverse is just a | |
27:05 | reflection of that function over a certain line . Can | |
27:07 | you spot what that line is ? The reflection of | |
27:11 | one to the other is going to be through this | |
27:14 | diagonal line right here . So let me take this | |
27:17 | off and try to draw this line . So this | |
27:22 | is where the mirror the mirror would lie if we | |
27:25 | were gonna actually flip this guy over here . So | |
27:28 | to get the inverse , all you do is you | |
27:30 | take the function graphically and you flip it over this | |
27:34 | red dot in line . And the red dotted line | |
27:36 | is a diagonal line , Y is equal to X | |
27:39 | . It's straight down the middle , it's Y . | |
27:41 | Is equal to X . Because the intercept zero and | |
27:43 | the slope here is one rise one run , one | |
27:47 | rise run rise one . So it's just a dotted | |
27:50 | line of a diagonal of 45 degrees , which means | |
27:52 | it goes right and it splits these guys into so | |
27:55 | graphically , you never do this graphically . But if | |
27:57 | I just said , hey , here's a function , | |
27:59 | right ? It's a line graph , it's inverse . | |
28:02 | All you would do is somehow mentally map all of | |
28:05 | these points across the dotted line here and then draw | |
28:08 | your line . And that would be the inverse function | |
28:09 | if the blue line , we're not an actual line | |
28:12 | but some other function . Because we're gonna have in | |
28:14 | verses of all kinds of functions , alright , then | |
28:17 | the same thing will hold if this if this um | |
28:20 | if this thing had some kind of squiggle in it | |
28:22 | , then we could still reflected over and we would | |
28:24 | have a different squiggly line , but it would be | |
28:26 | reflected over to the other side . That would be | |
28:28 | its inverse . Now , I want to talk about | |
28:31 | a couple of things , I want to mark a | |
28:33 | few really important points off of this graph . Okay | |
28:38 | , let's see what is this point right here , | |
28:40 | this is negative two comma one . This point right | |
28:42 | here is negative two comma one . How can I | |
28:46 | read that ? Negative two comma one . If I | |
28:47 | run it through this function right here , if I | |
28:49 | put negative two into here then I'm gonna get a | |
28:51 | negative one . I'm going to add it here , | |
28:53 | I'm gonna get a one . So negative two comma | |
28:54 | one . What other point is on this guy ? | |
28:56 | Let's go to -3 . And then what is this | |
28:59 | ? This intersection right here ? So at this point | |
29:02 | is negative three comma one half . You can just | |
29:06 | read it right off the graph . Here's one and | |
29:08 | here's one half there . If you put a negative | |
29:10 | three in here , you do the math here , | |
29:12 | you're gonna get one half out . All right . | |
29:14 | So , these points are also on the inverse function | |
29:18 | over here . But the way it works is what | |
29:21 | happens is these points are going to be exactly flipped | |
29:24 | around . So let's go and take a look at | |
29:25 | that by switching to black . And let's say , | |
29:28 | what would this point B the mirror image . In | |
29:30 | fact , you can see I already have it here | |
29:31 | . The mirror image when you reflect it over . | |
29:33 | Is this point so negative two comma one . This | |
29:36 | point becomes one comma negative too . Look at that | |
29:41 | and stare at it . What you've done is the | |
29:44 | inverse maps every point on the function to another point | |
29:48 | . That is kind of its mirror image cousin . | |
29:49 | But what happens is I take the coordinates and I | |
29:52 | flip them around . So negative two comma one becomes | |
29:54 | one comma negative too . And let's look at this | |
29:58 | . If I've taken literally go straight through this guy | |
30:00 | and down here , it's going to be this point | |
30:02 | right here , right ? Which is negative three comma | |
30:07 | I'm sorry , not negative three comma It's going to | |
30:09 | be 1/2 common negative 3 . 1 half , comment | |
30:14 | negative three . This is one half and then common | |
30:16 | negative three . It's right there . So this point | |
30:18 | maps with this one and this point maps with this | |
30:20 | one . Every point on this line is going to | |
30:22 | have a cousin partner point on the inverse line . | |
30:25 | And every point here is going to relate to every | |
30:27 | point here by simply taking the coordinates and flipping them | |
30:30 | backwards , taking the coordinates and flipping them backwards . | |
30:34 | And that flipping backwards business of taking every point on | |
30:38 | the function and flipping them backwards to make the inverse | |
30:42 | . That is why the functions undo each other . | |
30:44 | Right ? Because if you think about it , if | |
30:46 | this is the inverse , sorry , if this is | |
30:48 | the function and this is its inverse , then if | |
30:51 | I take any number in , let's say I put | |
30:53 | negative two as my input , I put negative two | |
30:56 | in . I get a one out but then I | |
30:58 | take that output and I stick it into the other | |
31:01 | function . I put a one in And what am | |
31:03 | I going to get a negative two out ? You | |
31:05 | can see I stick to take the output of this | |
31:07 | , stick it in here and I'm going to read | |
31:09 | off a negative two out . So I started with | |
31:12 | negative two . I ran it through this function . | |
31:14 | I run the output into the other function and then | |
31:17 | I get the same exact thing back , started with | |
31:19 | negative two And I ended with -2 . Right same | |
31:24 | thing here . If I stick as a starting point | |
31:26 | negative three in , I get a one half out | |
31:28 | . If I take that answer and put a one | |
31:30 | half into the other functions , I get a negative | |
31:32 | three out . So you see that's what we were | |
31:34 | doing all along here . I put a negative three | |
31:37 | in . Put it through both of the functions . | |
31:38 | I get a negative three out . I get exactly | |
31:40 | what I started with . Put a one in , | |
31:42 | put it through both functions and get a one out | |
31:44 | . Put a negative three in . Run it through | |
31:47 | , take this point , run it through . I | |
31:48 | get exactly what I started with . Start with a | |
31:50 | negative to get the intermediate . Run it through here | |
31:52 | . I get the negative two out . So graphically | |
31:55 | I'm showing you why this undoing business works . It's | |
31:59 | because this thing is a mirror image reflection over 45 | |
32:02 | degrees , which basically means every point here has to | |
32:05 | be flipped around like this , which means every time | |
32:08 | I stick it in , put in here and get | |
32:09 | a number out and then take that number here and | |
32:11 | get the corresponding number out . I'm going to get | |
32:13 | exactly what I started with . So the bottom line | |
32:17 | punchline most important thing I want you to get out | |
32:19 | of this other than the math that we've done before | |
32:22 | Is if a function has an inverse , if a | |
32:26 | function has an inverse , then that inverse will be | |
32:29 | that function reflected over a 45° line . Why is | |
32:33 | equal to X . This is the inverse function of | |
32:35 | this and the same thing goes true . If this | |
32:38 | is your input function then it's inverse will be the | |
32:40 | blue line . So it's not that It's not one | |
32:43 | way there in verses of each other . F is | |
32:45 | an inverse of G . & G is an inverse | |
32:48 | of f . And they're both mirror image reflections obviously | |
32:51 | over that line . 45° with the points flipping around | |
32:54 | . And that is why they undo each other . | |
32:57 | All right . So if you can , in your | |
32:58 | mind envision this being more complicated than a line and | |
33:01 | you can flip it over , you would still have | |
33:03 | the curve but it would be rotated down the same | |
33:05 | kind of thing would hold . All right . Um | |
33:09 | One more thing I want to talk about before we | |
33:11 | close because I've really pretty much gotten everything out that | |
33:14 | I want to get out . But one important thing | |
33:16 | I want to say before I get into go off | |
33:19 | to the to the very final end is that not | |
33:22 | all functions have in verses . Most of them do | |
33:26 | , but not all of them . I want to | |
33:27 | tell you really quickly how you can tell if a | |
33:30 | function has an inverse and we're gonna practice it more | |
33:31 | in the next lesson . Alright , for an F | |
33:34 | to pass for a function to have an inverse . | |
33:37 | It must pass what we call a horizontal line test | |
33:40 | basically . So four F of X to have an | |
33:45 | inverse . It must pass the horizontal line test . | |
33:53 | I'm not gonna write that out . Horizontal line test | |
33:55 | is very , very easy to understand . All right | |
33:57 | , let's take a look at this first of all | |
33:59 | . Let's look at what we have here . A | |
34:00 | horizontal line test means if you have a function and | |
34:04 | you start crossing a horizontal line through this function , | |
34:08 | it can only cross in one spot , horizontal line | |
34:10 | only cuts this function in one location anywhere . So | |
34:13 | that means when I map it then the inverse function | |
34:16 | will pass the vertical line test . Because for a | |
34:19 | function to be a function it has to pass the | |
34:21 | vertical line test . So if you're going to say | |
34:23 | this thing has an inverse function , you you need | |
34:26 | to make sure it passes a horizontal line test so | |
34:28 | that when you flip it it'll pass a vertical line | |
34:30 | test to be a function . So let's take a | |
34:34 | look at something that doesn't have an inverse . Right | |
34:36 | . As an example , let's say we have a | |
34:38 | graph here and we have our nice friendly parabola ffx | |
34:44 | , his ex square . Does this function have an | |
34:46 | inverse over this whole domain like this ? Well , | |
34:48 | all you have to do is say , well does | |
34:50 | it pass a horizontal line test ? Well no fail | |
34:55 | the horizontal line test because it cuts into locations . | |
35:00 | If it cuts in more than one location then uh | |
35:03 | it's not gonna work now . What would happen if | |
35:05 | you actually tried to construct an inverse with this thing | |
35:08 | ? Right ? What would happen ? Remember ? The | |
35:09 | inverse function would just be the mirror image reflection of | |
35:12 | this thing over that 45 degree line right here . | |
35:15 | So what would happen is the inverse function would be | |
35:18 | something like this because if you remember that 45 degree | |
35:21 | line is somewhere somewhere like this . So the original | |
35:25 | function was like this . You flip it over . | |
35:27 | The inverse would be something like this . But the | |
35:30 | inverse has to be a function . And remember all | |
35:33 | functions have to pass the vertical line test . This | |
35:36 | thing fails the vertical line test because it cuts in | |
35:39 | more than one location . So the reason this thing | |
35:42 | doesn't have an inverse , the reason we have a | |
35:43 | horizontal line test is because once you mirror image reflected | |
35:47 | it has to pass a vertical line test . So | |
35:49 | if it has to pass , if it fails a | |
35:51 | vertical line test and it's going to fail a horizontal | |
35:53 | line test for the original function . So in most | |
35:56 | books , what you see is they'll tell you , | |
35:58 | you know , if a function has an inverse , | |
36:00 | it has to pass a horizontal line test . All | |
36:04 | lines are gonna pass or except for horizontal lines are | |
36:07 | going to pass horizontal line test , right ? So | |
36:10 | all lines have an inverse . But this parabola over | |
36:14 | this entire domain like this does not have an inverse | |
36:16 | . So you that's what you would write down on | |
36:17 | your test . But other functions that we could draw | |
36:19 | will have an inverse . And in the next lesson | |
36:21 | we're gonna get a little bit more practice with that | |
36:24 | . So we have learned a lot in this lesson | |
36:27 | . It's a really important topic because inverse functions feed | |
36:30 | into so many of the more advanced kind of uh | |
36:34 | lessons in the curriculum . Whatever your classes studying , | |
36:36 | pre calculus , calculus , or algebra , inverse functions | |
36:39 | feed into that . We talked about an additive inverse | |
36:42 | . All we're doing is when we add something , | |
36:44 | we have an inverse to undo it , we get | |
36:46 | the same number back , We get the same number | |
36:49 | back with multiplication by essentially multiplying by a fraction or | |
36:52 | division , uh to get the same number back . | |
36:55 | And then we said , functions can have inverse is | |
36:57 | also these are inverse functions . Now we know why | |
37:00 | with their graphs because their reflection across the 45° line | |
37:04 | like that , but basically , whatever number we put | |
37:06 | into this thing , we're going to get it back | |
37:08 | once we run it through both of the functions . | |
37:10 | And we prove that is true by relaxing the numbers | |
37:13 | and just letting the input be a variable . You | |
37:15 | run it through , you get the same number out | |
37:17 | that you put in , you flip the order . | |
37:18 | You run it through , you get the same number | |
37:20 | out that you put it in . So inverse functions | |
37:23 | are inverse , is if you run it through both | |
37:26 | of the functions and get the same thing out , | |
37:28 | no matter the order in which you Uh execute that | |
37:31 | guy . Then we plotted both of those functions and | |
37:34 | showed that the line in this case of the function | |
37:38 | has an inverse by reflecting it over a 45° line | |
37:41 | like this . And we said that every point on | |
37:43 | the original function has a corresponding point on the inverse | |
37:46 | function where the coordinates are flipped around . And the | |
37:48 | reason the inverse functions undo each other is because of | |
37:52 | those coordinates flipping around . So if I stick a | |
37:54 | number into the original function , I get an intermediate | |
37:57 | number out . I take that number into the other | |
37:59 | function and I get the same number in that eye | |
38:02 | out that I stuck in to begin with . And | |
38:04 | that will happen for any number that you put into | |
38:07 | this inverse function pair . It's a lot of material | |
38:11 | . But make sure you understand this concept because in | |
38:13 | the next lesson we're going to be calculating the inverse | |
38:16 | function , figuring out what the inverse . I just | |
38:19 | told you these are inverse funds . I didn't tell | |
38:20 | you how to figure it out . I just said | |
38:21 | here they are . In the next lesson , we | |
38:23 | want to actually calculate what the inverse function is and | |
38:27 | sketch them and figure out if it passes the horizontal | |
38:29 | line test and all of that stuff . So make | |
38:31 | sure you understand this . Follow me on to the | |
38:32 | next lesson will continue working with inverse functions in algebra | |
38:37 | , pre calculus and calculus . |
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