Solving Inequalities Using Multiplication or Division - By Anywhere Math
Transcript
00:0-1 | Welcome anywhere . Math . I'm Jeff Jenkinson and today | |
00:02 | we're solving inequalities using multiplication or division . However , | |
00:08 | there will be no negative numbers in this video . | |
00:12 | So with that let's get started . Okay , example | |
00:32 | one solve X over five is less than or equal | |
00:35 | to two and then grab the solution . Well , | |
00:39 | solving inequalities using multiplication or division is just like solving | |
00:44 | equations with multiplication or division . As long as you're | |
00:49 | not multiplying or dividing negative numbers . And in this | |
00:52 | video it's all going to be positive . So it's | |
00:55 | gonna be like the same . It's going to be | |
00:57 | just like doing it with equations . Our goal is | |
01:00 | to get the variable alone right now . X is | |
01:02 | being divided by five . So I do that inverse | |
01:05 | operation and multiply this side by five to get that | |
01:09 | X alone and anything I do to one side , | |
01:11 | I have to do the same to the other side | |
01:14 | to make sure the inequality stays true . So here | |
01:17 | we go . Uh X over five . If I | |
01:19 | multiply this side by five Less than or equal to | |
01:22 | . To do the same thing on this side multiply | |
01:25 | that side by five . Those fives will cancel out | |
01:29 | . And I'm left with X is less than or | |
01:31 | equal to 10 . Okay , I've solved it now | |
01:35 | . Let's grab that solution . Here is my quick | |
01:40 | Number line . I know x needs to be less | |
01:43 | than or equal to 10 . So maybe here is | |
01:45 | zero , there is 10 less than or equal to | |
01:50 | because it's or equal to . That means my dot | |
01:53 | needs to be like that filled in Arrow going towards | |
02:00 | the less than theirs . Example one here's some to | |
02:03 | try on your own . Okay , example to solve | |
02:13 | for N is greater than 32 and then grab the | |
02:16 | solution . So same thing . I'm trying to get | |
02:19 | the variable alone . I notice and is being multiplied | |
02:22 | by four . So the inverse operation of multiplication is | |
02:26 | division divided by four . Well undo that multiplication and | |
02:30 | then I do the same thing here . So four | |
02:33 | end is greater than 32 . I'm going to divide | |
02:36 | this side by four , which means I'm also gonna | |
02:39 | divide that side by four to make sure the inequality | |
02:43 | stays true . Uh those get cancelled out and I | |
02:46 | get N is greater than 32 , divided by four | |
02:50 | , is eight . Okay , um This represents all | |
02:54 | my solutions to this inequality . Any number that's greater | |
02:57 | than eight would be a solution to this inequality . | |
03:01 | So let's graph that here is a quick little number | |
03:06 | line . I'm gonna be at eight , let's say | |
03:09 | eight is here let's go 89 10 , something like | |
03:14 | that at eight because it's greater than it's not greater | |
03:18 | than or equal to . I'm going to have an | |
03:20 | open circle and greater than which means the arrows going | |
03:24 | to the right . So again , This arrow represents | |
03:29 | all the solutions to this inequality . Any number that's | |
03:34 | greater than eight would be a solution , right ? | |
03:38 | 10 would be a solution because four times 10 is | |
03:40 | 40 that's greater than 30 to 9 would be a | |
03:43 | solution . Four times nine is 36 that's greater than | |
03:46 | 32 . A million would be a solution . Anything | |
03:49 | greater than eight . Let's try one more . Example | |
03:52 | , example three A one day pass to a gym | |
03:55 | cost $4.50 a 30 day pass for like a month | |
03:58 | long pass cost $45 . So part a right And | |
04:02 | solving inequality to find when it's better to buy the | |
04:06 | one day passes instead of buying the full month long | |
04:10 | , 30 day pass . So this is very typical | |
04:13 | right ? New Year's resolutions . People say , okay | |
04:15 | , I want to go to the gym . Well | |
04:17 | , is it better to buy the month long pass | |
04:19 | or is it better to buy or to pay each | |
04:22 | time you go ? Well , it depends on how | |
04:24 | often you go , which is exactly what we're trying | |
04:26 | to find out here . So uh let's look , | |
04:30 | a one day pass costs $4.50 . The month long | |
04:35 | is $45 . Now , the one thing we don't | |
04:39 | know , it's how often we're gonna go , how | |
04:42 | many days we're going to go ? That's gonna be | |
04:44 | our variable , right ? Whenever you're writing inequalities or | |
04:48 | equations , always think what's your variable gonna be , | |
04:51 | what , don't , you know ? And in this | |
04:52 | case we don't know how often how many days we're | |
04:56 | going to go to the gym . So that's gonna | |
04:57 | be my variable . I'm gonna call that d the | |
05:00 | for days Uh to the gym . Well , each | |
05:03 | day costs $4.50 . So this will become 4.5 d | |
05:11 | . Right ? $4.54 . 50 cents times the number | |
05:14 | of days you go now , what we're looking for | |
05:18 | is when it's going to be cheaper , right ? | |
05:22 | When it's better to do the one day passes and | |
05:26 | it would be better when this cost is cheaper than | |
05:32 | The $45 than the month long . So to show | |
05:35 | that this is cheaper or a better deal , we | |
05:37 | would make it less than 45 . So take a | |
05:44 | second and just look at that and think about what | |
05:46 | we what we wrote . So what we're saying is | |
05:49 | $4.50 times the number of days , right ? Is | |
05:56 | less than if that's less than $45 , which is | |
06:00 | the month on pass . This would be the better | |
06:03 | deal . So now let's solve it . So we | |
06:05 | wrote the inequality now let's solve it . Uh divide | |
06:09 | both sides by 4.5 . To get that d . | |
06:12 | That variable alone . D . Is less than , | |
06:18 | well 45 divided by 4.5 is 10 . You can | |
06:24 | do that over here or just trust me . Uh | |
06:28 | What that means is when is it better to buy | |
06:31 | a one day pass ? Well it's better to buy | |
06:33 | a one day pass if You go less than 10 | |
06:38 | days . So there is our answer . Let's try | |
06:41 | one more . Okay . Same problem . We're just | |
06:43 | gonna do part B . And part C . When | |
06:46 | would the cost be equal ? The cost would be | |
06:48 | equal if you went exactly 10 days , Right ? | |
06:53 | If you in 10 days 10 times $4.50 would be | |
06:57 | $45 . If you went 10 days with a month | |
07:00 | passed . Well still $45 and last one . When | |
07:03 | would it be better to buy the 30 day pass | |
07:06 | ? Well , if it was cheaper To buy the | |
07:10 | day pass , if you went less than 10 days | |
07:14 | And if you do exactly 10 days , it doesn't | |
07:16 | matter . Well then if you go more than 10 | |
07:19 | days , the 30 day pass would be the better | |
07:22 | deal . Because after every day above 10 , it | |
07:26 | doesn't matter . You don't get charged anymore because it's | |
07:29 | just a 45 straight $45 a straight fee . No | |
07:33 | matter if you go 11 , 12 , 13 , | |
07:36 | if you go 25 days or if you go all | |
07:38 | 30 right , that would be the better deal . | |
07:41 | Because if we did 30 days and pay $4.50 each | |
07:44 | day . Well , 30 times 45 is gonna be | |
07:47 | much greater than 45 days . Okay ? Here are | |
07:51 | some to find your own as always . Thank you | |
08:01 | so much for watching . And if you like this | |
08:03 | video , please subscribe . |
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