SAT Math Part 3 - Solving Rational Equations and Factoring Trinomials - By The Organic Chemistry Tutor
Transcript
00:0-1 | number 14 . Which of the following ? Could be | |
00:03 | a value of X . So we have a rational | |
00:07 | equation . 10 over X minus two is equal to | |
00:10 | X plus one . How can we calculate the value | |
00:14 | of X ? Well what I recommend doing is getting | |
00:19 | rid of the fraction . So let's multiply everything by | |
00:23 | X . So 10 over X times X . The | |
00:27 | X variables will cancel Given us just 10 X times | |
00:33 | negative two is negative two X . And then X | |
00:37 | times X is X squared X Times one is X | |
00:41 | . So this is what we have . Now let's | |
00:44 | take everything from the left side and move it to | |
00:47 | the right side . As we move -2 x to | |
00:51 | the right side , it's going to change from negative | |
00:54 | two X To positive two x . And as we | |
00:59 | move positive 10 from the left to the right side | |
01:02 | it's gonna become negative 10 . So this is what | |
01:05 | we have now let's go ahead and combine like terms | |
01:10 | . So we have X Plus two X which is | |
01:13 | Drea Acts and thus we have X squared plus two | |
01:17 | , reaction minus 10 . So now we have a | |
01:23 | try no meal with the lien coefficient of one . | |
01:26 | So let's go ahead and factor that expression . So | |
01:29 | what two numbers multiply 2 -10 But add to positive | |
01:34 | three . So we know five and 2 Will give | |
01:40 | us 10 . If we multiply the two numbers now | |
01:43 | , should we make The five negative or the two | |
01:46 | negative -2 Plus five is positive three . So the | |
01:51 | two has to be negative . Does two factor it | |
01:54 | ? It's going to be X plus five And X | |
01:58 | -2 . So let's set each factor equal to zero | |
02:07 | , Subtracting five from both sides . We get the | |
02:11 | first solution . Acts is equal to negative five and | |
02:15 | for the other one adding tunable sites gives us The | |
02:19 | other answer acts as equal to two . Now this | |
02:24 | answer is not listed . So A is the correct | |
02:28 | answer . Choice acts is equal to negative five , | |
02:32 | number 15 . Which of the following could be a | |
02:36 | value of X . And the equation shown below . | |
02:40 | So here we have two fractions separate by an equal | |
02:43 | sign . But with many try no meals . So | |
02:47 | let's factor let's begin by factor in the first expression | |
02:51 | X squared minus two X minus 24 . So let's | |
02:56 | look for two numbers that multiply to negative 24 but | |
03:00 | add to negative two . So this is gonna be | |
03:04 | negative six and positive for So I'm going to buy | |
03:08 | the as X -6 Times X-plus four . Now , | |
03:13 | what about the tree ? No mia on the bottom | |
03:15 | left . So what ? two numbers Multiply 2 , | |
03:19 | 12 . But at 2 , 7 Factors of 12 | |
03:23 | are one in 12 , two and 6 , three | |
03:26 | and 4 . But 3-plus 4 adds up to seven | |
03:30 | . So it's going to be X plus tree times | |
03:34 | X plus four . Now , for the last one | |
03:39 | on the bottom , right ? Two numbers that multiply | |
03:41 | to negative six but adds a positive one . It | |
03:44 | would be positive three A negative too . So we | |
03:48 | have X plus two eight times X minus two . | |
03:55 | Now , before we move on to our next step | |
03:58 | , it's important to understand that We cannot have a | |
04:01 | zero in the denominator . So the X values that | |
04:06 | would produce zero and the denominator would make the function | |
04:09 | undefined . So because we have the X plus three | |
04:12 | factor on the bottom , X cannot equal -3 . | |
04:17 | Here we have X plus four , so X cannot | |
04:20 | be negative for and here we have X -2 . | |
04:24 | So X cannot equal to -4 is one of the | |
04:29 | answer choices . Since it would make The expression or | |
04:33 | the function under fine . We can eliminate negative four | |
04:37 | as an answer choice . So now what we can | |
04:43 | do at this point is cancelled , we can cancel | |
04:45 | X-plus four . And if we multiply the right side | |
04:50 | and the left side by X plus story , we | |
04:53 | could cancel the explanatory factors . So what we have | |
05:01 | left over which I'm gonna right at the top , | |
05:07 | We have X -6 on the right side , I | |
05:09 | mean on the left side and on the right side | |
05:11 | we have 12 Over X -2 . So what do | |
05:17 | you think we need to do at this point in | |
05:18 | order to solve the equation ? What is our next | |
05:21 | step ? Now let's write X -6/1 . So now | |
05:27 | we have two fractions separated by an equal sign . | |
05:31 | So we can cross multiply . So we're going to | |
05:34 | have one times 12 which is 12 . And then | |
05:37 | we're going to multiply X -6 by X -2 . | |
05:42 | Our next step is to foil . So we're gonna | |
05:47 | multiply X by X which is X squared . And | |
05:51 | then x times negative two And the -6 times x | |
05:55 | . And then negative six times negative two , which | |
05:57 | is positive 12 . Now subtract in both sides by | |
06:03 | 12 . We're going to have zero is equal to | |
06:07 | X squared And then we can combine these 2 -2 | |
06:11 | . X -6 . X is negative attacks . Our | |
06:16 | next step is to factor the G C . F | |
06:18 | . The greatest common factor , which in this case | |
06:21 | is going to be X . So we can factor | |
06:24 | this expression as x times X -8 . Now , | |
06:30 | what we're going to do is set each factor equal | |
06:31 | to zero . So we have X is equal to | |
06:34 | zero . And if you set X -8 equal to | |
06:37 | zero When you saw that , you'll get access equal | |
06:39 | to eight . Now zero is not one of the | |
06:42 | solutions , but eight is , so E is the | |
06:46 | correct answer choice for this problem . |
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