How To Prove The Quadratic Formula By Completing The Square - By The Organic Chemistry Tutor
Transcript
00:00 | in this video , we're going to talk about how | |
00:02 | to derive the quadratic formula . Starting from this equation | |
00:08 | , A X squared plus bx plus C Is equal | |
00:11 | to zero . The quadratic equation . So how can | |
00:15 | we derive this particular formula X is equal to negative | |
00:19 | B plus or minus the square root of B squared | |
00:24 | minus four A . C . All divided by two | |
00:27 | way in order to derive that formula . What we | |
00:33 | need to do is we need to solve for X | |
00:36 | and we have to complete the square in order to | |
00:39 | do so . So let's get rid of this to | |
00:44 | make more space . The first thing I'm gonna do | |
00:49 | is I'm going to take the constant term C and | |
00:51 | move it to the other side of the equation . | |
00:54 | So we're gonna have a X squared plus bx . | |
00:59 | Leave A . Space equals negative C . Now the | |
01:05 | next thing that we need to do is divide everything | |
01:08 | by A . So they will cancel here , we're | |
01:14 | going to have X squared plus B over a , | |
01:19 | times X is equal to negative C over A . | |
01:25 | So now at this point we need to complete the | |
01:27 | square in order to do that , we need to | |
01:31 | take half of that coefficient B over A 1/2 times | |
01:36 | b over a . Is B over two a . | |
01:41 | So we're going to add that to both sides of | |
01:43 | the equation , but we need to square this result | |
01:45 | , so we're gonna add plus B over two A | |
01:50 | squared . Whatever you do to the left side , | |
01:53 | you must also due to the right side , so | |
01:56 | that the value on both sides of the equation remain | |
02:00 | the same . So now at this point we need | |
02:10 | to factor the perfect square . Try no meal that | |
02:13 | we have on the left side . A quick and | |
02:16 | simple way to factor a perfect square . Try no | |
02:18 | meal is to follow these steps , it's going to | |
02:21 | be X , whatever variable you see there and then | |
02:24 | whatever sign you see here plus whatever is here before | |
02:29 | its squared . So X plus B over two A | |
02:33 | squared . That's a very quick and simple way to | |
02:37 | factor a perfect square . Try no meal on the | |
02:39 | right side , we can go ahead and square that | |
02:42 | term . So it's gonna be B squared over to | |
02:46 | a squared is going to be for a squared . | |
02:54 | Now the next thing that we want to do is | |
02:55 | we want to convert This expression from two fractions into | |
03:01 | one fraction . And so to combine two fractions into | |
03:04 | one , you need to get common denominators . Therefore | |
03:07 | we're going to multiply The top and bottom of sea | |
03:10 | over a by four a . So we're gonna have | |
03:16 | X plus B over A . I mean , B | |
03:20 | over two A squared , and that's going to be | |
03:26 | equal to B squared over four A squared minus . | |
03:30 | So we have four a . c over four A | |
03:33 | squared . So now that we have common denominators , | |
03:37 | we can combine it into a single fraction . So | |
03:40 | this is going to be b squared minus four A | |
03:43 | . C . All over for a squared . Now | |
03:52 | , what do you think is the next thing that | |
03:54 | we need to do at this point ? Remember our | |
03:59 | goal is to isolate X . We need to solve | |
04:02 | for X . So what we need to do is | |
04:04 | take the square root of both sides . The square | |
04:08 | root and the square will cancel . And so we | |
04:11 | no longer need to write the parentheses . So it's | |
04:13 | simply going to be X plus B over to A | |
04:19 | . And then that's going to be the square root | |
04:22 | of B squared minus four A . C . Now | |
04:25 | the square root of for a squared , we could | |
04:28 | simplify that . The square root of four is to | |
04:31 | the square root of a square is eight . Now | |
04:34 | , because we took the square root of the right | |
04:35 | side , we can add plus or minus . The | |
04:40 | next thing we need to do is subtract wolf sides | |
04:43 | by this term or simply move it from the left | |
04:46 | side to the right side . It's positive on the | |
04:48 | left side , but it's going to be negative on | |
04:50 | the right side . So we're gonna have X is | |
04:58 | equal to negative B over to a plus or minus | |
05:02 | the square root of B squared minus four A C | |
05:06 | over two A . Now that we have common denominators | |
05:12 | , we can combine that into a single fraction . | |
05:17 | So this is going to be negative B plus or | |
05:19 | minus the square root of B squared minus four A | |
05:23 | . C . All over two . A . And | |
05:27 | so that's how you can prove or derive the quadratic | |
05:32 | formula starting from the quadratic equation . The key is | |
05:37 | to complete the square and then solve for X . |
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