Geometry Introduction - Basic Overview - Review For SAT, ACT, EOC, Midterm Final Exam - By The Organic Chemistry Tutor
Transcript
00:00 | this video is a basic geometry view for those who | |
00:03 | are taking the S . A . T . Or | |
00:05 | the H . T . Exam . And if you're | |
00:07 | taking a geometry final exam you could benefit from this | |
00:10 | video too . So let's go over some common shapes | |
00:13 | and the formulas they need to know . So let's | |
00:16 | say if we have a circle and my drawing is | |
00:18 | not that great but Let's work with it . And | |
00:22 | let's say that the radius of the circle is five | |
00:27 | given the radius , what is this ? A conference | |
00:30 | of the circle ? And also what is the area | |
00:34 | ? The first formula you need to know , the | |
00:35 | circumference is two pi R . So therefore it's going | |
00:41 | to be two pi times five Which is 10 lbs | |
00:47 | . Mhm . So that's the exact answer . Sometimes | |
00:50 | you may need to put this in your chocolate and | |
00:53 | get a decimal value . So you could use the | |
00:56 | fact that pie is about 3.1416 . So this is | |
01:03 | going to be 31 416 So that's the circumference . | |
01:08 | Now , what is the equation for the area of | |
01:10 | a circle ? The area of a circle is pi | |
01:16 | r squared . So for this particular example it's pi | |
01:20 | times five squared , Five squared is 25 , so | |
01:23 | the area is 25 5 . So 25 times I'm | |
01:30 | going to use the exact value As a decimal , | |
01:32 | that's 78 0.54 . Now what about the diameter if | |
01:38 | you know the radius of the circle , what is | |
01:40 | the diameter ? So the radius is between the center | |
01:44 | of the circle and it touches any point on the | |
01:47 | circle . That's the radius . The diameter also passes | |
01:52 | through the center of the circle but it's a distance | |
01:54 | from one edge of the circle all the way to | |
01:56 | the other edge and it always has to pass through | |
01:59 | the center of the circle . If you have a | |
02:02 | line that touches two points in a circle but doesn't | |
02:05 | pass through the circle , I mean the center of | |
02:07 | the circle that is , it's a cord . So | |
02:10 | this line it touches these two points on a circle | |
02:13 | but it doesn't pass the center of the circle , | |
02:15 | so that makes the court . But a diameter is | |
02:19 | between two points on the edge of the circle and | |
02:21 | the diameter passes through the center of the circle . | |
02:24 | So make sure you know the difference between the diameter | |
02:26 | and the court . The diameter is twice the value | |
02:29 | of the radius is to our , So in this | |
02:32 | case two times 5 is 10 . So for a | |
02:35 | circle these are the three main equations , you need | |
02:37 | to know the circumference two pi r the area pi | |
02:41 | r squared and the diameter is twice the length of | |
02:44 | the radius . Now the next shape that we're going | |
02:48 | to talk about is the square . So let's say | |
02:52 | that The side length of the square is eight . | |
02:57 | What is the area ? And what is the perimeter | |
02:59 | of the square ? The area of a square is | |
03:04 | basically side squared . All sides of the square are | |
03:09 | the same . So in this case asks is eight | |
03:12 | . So the area is just gonna be eight squared | |
03:14 | , which is 64 square units , not to find | |
03:18 | the perimeter . The perimeter is the sum of the | |
03:21 | four sides , it's S plus S plus S plus | |
03:25 | S . If you add S four times , it's | |
03:28 | the same as four times s So the perimeters four | |
03:31 | times 8 . So it's 32 units long . So | |
03:35 | make sure you know those two equations for square , | |
03:37 | the area is side squared . The perimeter is simply | |
03:40 | the sum of all four sides . Or for us | |
03:45 | . Now , here's a question for you . Going | |
03:48 | back to the square , let's say the area is | |
03:51 | 36 square feet , What is the perimeter of the | |
03:56 | square ? So we know that the area is s | |
04:02 | squared by the way for each of these questions , | |
04:04 | pause the video and see if you can figure it | |
04:07 | out . So the area is 36 . If we | |
04:10 | take the square root of both sides we can get | |
04:14 | the life of each side So each side is six | |
04:18 | units long . Therefore the perimeter is six plus six | |
04:23 | plus six plus 64 times Or four times six . | |
04:26 | So it's 24 ft long . That's the perimeter . | |
04:32 | Now going back to the circle , let's say if | |
04:39 | we're given the circumference of the circle , Let's say | |
04:42 | the circumference is 16 lbs . With this information , | |
04:46 | find the left of the diameter and also the area | |
04:49 | of the circle . So first we need to find | |
04:53 | the radius . We know that the circumference is two | |
04:56 | pi R . And the circumference is 165 . So | |
05:01 | what we need to do is divide both sides by | |
05:04 | two pi . So two pi divided by two pies | |
05:10 | , 1 here , the pies cancel . So the | |
05:12 | radius is 16 divided by two . So it's eight | |
05:15 | units long . If you have the radius , you | |
05:17 | can easily find the diameter . The radius is twice | |
05:20 | the length of the diameter , So it's 16 units | |
05:24 | . So now we can find the area which is | |
05:25 | simply pi R . Squared . So it's pi times | |
05:29 | eight squared Or simply 64 pi . So that's the | |
05:34 | area . Now let's say if you have a rectangle | |
05:38 | And let's see the left of the rectangles , 10 | |
05:41 | And the width is five . What is the area | |
05:44 | and what is the perimeter of directing ? Feel free | |
05:48 | to pause the video and find these two things . | |
05:52 | So this is the left , This is the west | |
05:55 | , this side is also the witnesses . The length | |
05:57 | , the area is simply lap times with the perimeter | |
06:00 | is two . L plus two . W . So | |
06:03 | the area is going to be 10 times five . | |
06:06 | So it's 50 square units . The Perimeter is going | |
06:10 | to be two times 10 Plus two times 5 . | |
06:14 | Two times 10 is 22 times five is 10 , | |
06:17 | 20 plus 10 is 30 . So the perimeter is | |
06:22 | 30 units long And the area is 50 square units | |
06:30 | . So let's say if the area is 40 units | |
06:39 | long and let's say the length is eight units . | |
06:47 | What is the perimeter of the rectangle ? Go ahead | |
06:51 | and try that problem . So the left is eight | |
06:55 | . We don't know the with but we could find | |
06:58 | the winner by using this equation . So 40 is | |
07:01 | equal to eight times w . So w . is | |
07:04 | 40 divided by eight , so it's five minutes long | |
07:07 | . And then once you have the with you can | |
07:12 | now find a perimeter , this is going to be | |
07:15 | two L plus two W . So it's uh two | |
07:19 | times eight plus two times five And at 16 plus | |
07:24 | 10 Which is 26 . So here is the practice | |
07:30 | problem . You could try so go ahead and take | |
07:32 | a minute and see if you can figure it out | |
07:34 | . The left of a rectangle is three , more | |
07:36 | than twice the whiff . If the area is 44 | |
07:40 | square cm , what is the perimeter of the rectangle | |
07:46 | ? So take a minute and work on that problem | |
07:49 | . So let's draw a picture . So this is | |
07:54 | the left , this is the wife . Now let's | |
07:56 | write an equation the length A stream or or three | |
07:59 | plus twice the width , that's two W . And | |
08:04 | we know the area is 44 square units . What | |
08:08 | is the perimeter of a rectangle ? If we could | |
08:11 | find the left and the whiff and then we could | |
08:14 | find the perimeter , The area , we know it's | |
08:17 | a lot of times with and what we can do | |
08:20 | if we want to is we can replace out with | |
08:24 | three plus two W . So we can get the | |
08:26 | area equation in terms of W alone . So you | |
08:29 | got to solve this by substitution . So three plus | |
08:32 | 2 W Times W is equal to 44 . Now | |
08:37 | let's distribute W . So W time stream is www | |
08:41 | W times to W is to w squared . Now | |
08:44 | let's move the 44 from the left side to the | |
08:46 | right side . So zero is equal to two W | |
08:50 | squared plus three W minus 44 . So what we | |
08:54 | have is the train , Omiya or quadratic expression . | |
08:57 | And we need to factor in order to find the | |
08:59 | value of W . So how can we factor this | |
09:02 | particular train oatmeal ? What we need to do first | |
09:05 | is multiplying the leading coefficient , which is to By | |
09:11 | the constant term -44 two times negative 44 is negative | |
09:16 | 88 . So what's your numbers multiply two . Negative | |
09:20 | 88 . But add to the middle coefficient three , | |
09:25 | This is positive 11 and -8 . 11 plus negative | |
09:29 | eight as up to three . But they multiply its | |
09:31 | negative 88 . So now what we're gonna do is | |
09:34 | we're going to replace the middle term www With 11 | |
09:39 | . w . -8 W . So it's gonna be | |
09:42 | zero is equal to two . W squared minus eight | |
09:45 | W . Plus 11 W -44 . I wanted to | |
09:51 | put the 11 next to the 44 because 44 is | |
09:54 | a multiple of 11 and eight is a multiple of | |
09:57 | two . So , and the next step , we're | |
09:59 | gonna factor by grouping and that's why I've arranged it | |
10:02 | the way I did . So in the first two | |
10:04 | terms , let's take off the G C F . | |
10:07 | The greatest common factor is to W two W squared | |
10:12 | divided by two W . That's going to be W | |
10:15 | -8 W divided by two . W is negative four | |
10:19 | In the last two terms . Let's take out an | |
10:22 | 11 and let's get rid of some of this stuff | |
10:25 | over here . Actually , I'm gonna need that solicitous | |
10:32 | , get rid of this and I don't think I | |
10:35 | need this for now . So we take out an | |
10:41 | 11 , 11 w divided by 11 is W And | |
10:46 | -44 divided by 11 . That's negative for So now | |
10:51 | let's factor W -4 . When those two terms are | |
10:55 | the same , that means that you're on the right | |
10:57 | track , you've done everything correctly so far . So | |
11:01 | if we take out W -4 from this term , | |
11:04 | What we're going to have left over is the two | |
11:05 | W . And if we take it out from the | |
11:07 | second term We're going to have 11 left over , | |
11:10 | but it's gonna be plus 11 . So now what | |
11:13 | we need to do is set both factors W -4 | |
11:16 | And so w plus 11 equal to zero . So | |
11:20 | if we add four to both sides we can see | |
11:22 | that W is equal to four . And the other | |
11:26 | equation we gotta start by subtracting both sides by 11 | |
11:30 | , so W . Two W . Is equal to | |
11:31 | negative 11 . And if we divide by two W | |
11:35 | is -11 over to now we're going to get rid | |
11:38 | of the negative answer because we're dealing with a real | |
11:40 | life object And to have a side length of negative | |
11:44 | 5.5 doesn't make sense . So we're going to choose | |
11:47 | this value W . Is equal to four . So | |
12:02 | if W . Is for We can now find the | |
12:05 | length which is 3-plus 2 W . Or three plus | |
12:09 | two times four . So that's three plus eight and | |
12:12 | that's 11 . Mhm . So the left is 11 | |
12:15 | and the wife is for And we can see why | |
12:18 | the area is left times with four times 11 Which | |
12:21 | is 44 . So that works out now . We | |
12:24 | can find the perimeter , the perimeter is two L | |
12:26 | . Plus two W . So that's two times 11 | |
12:31 | plus two times for it . And so that's 22-plus | |
12:35 | 8 which is 30 . So that's the answer to | |
12:39 | this particular problem . That's the permanent of the rectangle | |
12:42 | by the wing . For those of you who are | |
12:44 | taking the A . C . T . Exam or | |
12:46 | the S . A . T . Exam . When | |
12:49 | you get a chance , go to Youtube and search | |
12:52 | out my ACT math video and satellite map video . | |
12:55 | You can get more examples than multiple choice practice problems | |
12:58 | . If you want to practice and prepare for the | |
13:01 | mass sections of those exams , I'm also going to | |
13:04 | post it At the last 20 seconds in the end | |
13:07 | of this video . So you can find the link | |
13:09 | there as well or you just search it to YouTube | |
13:11 | . You should come up but let's continue with this | |
13:14 | problem . The left of a rectangle is three more | |
13:18 | than its with . If the Perimeter is 26 what | |
13:22 | is the area of the rectangle ? So go ahead | |
13:25 | and try that problem . Now we know the perimeter | |
13:29 | is two L . Plus two W . So 26 | |
13:35 | is equal to two hour plus two . W . | |
13:38 | Now notice that we could simplify this equation . Let's | |
13:42 | divide everything by two . So 13 is equal to | |
13:48 | L plus W . Our goal is to find the | |
13:51 | area of the rectangle . If we could find the | |
13:54 | dimensions , if we could find the left and the | |
13:56 | wife then we could easily find the area . Now | |
13:59 | we're told that the length is three more than its | |
14:02 | with . So L . Is three plus W . | |
14:06 | So we're going to do at this point is replaced | |
14:08 | out With three plus W . So 13 is equal | |
14:12 | to three plus W plus W . So that's three | |
14:17 | plus 2 . W . Now we can find the | |
14:19 | value of W less , attract both sides by three | |
14:23 | , so 10 is equal to two W . And | |
14:26 | if we divide both sides by two , 10 divided | |
14:29 | by two is 5 . so w . s . | |
14:31 | five L . A . Stream more than W . | |
14:34 | So three Plus 5 is eight . So L . | |
14:39 | S . A . So we have the with and | |
14:43 | we have the left . Now we know that the | |
14:46 | area is lifetimes with Or eight times 5 . So | |
14:51 | it's 40 square units . And that's the answer . | |
14:57 | Now let's talk about triangles . Let's say if we | |
15:00 | have a right triangle and was saying One side , | |
15:05 | one of the legs mystery and the other leg is | |
15:07 | four . What is the high partners of the triangle | |
15:12 | ? Yeah . Let's call this side A . B | |
15:16 | . And C . According to the protagonist . Um | |
15:19 | A squared plus B squared is equal to C squared | |
15:23 | . So we can say A stream B . Is | |
15:25 | for . And let's find see three squared is 94 | |
15:29 | squared is 16 And nine plus 16 is 25 . | |
15:34 | So if you take the square root of 25 , | |
15:38 | This will give you five . So the length of | |
15:40 | the hypotenuse which is the side across the 90° angle | |
15:44 | represented by this box . That is five minutes long | |
15:50 | . Let's try another example . Let's see . The | |
15:53 | hypotenuse is 13 minutes long And one of the legs | |
16:02 | is five . Find miss inside . And I need | |
16:06 | to know some special numbers for a right triangle . | |
16:10 | There's the 345 triangle , There's the 5 12 13 | |
16:15 | Triangle , Which is the one that we need to | |
16:18 | notice that the missing side is 12 . And some | |
16:20 | other ones they need to know is the 7:24 25 | |
16:24 | triangle . The 8 1517 Triangle . There's the 9 | |
16:30 | 40 41 triangle And also the 1160 61 Triangle . | |
16:35 | So if you know these triangles , you don't have | |
16:37 | to use the pythagorean theorem formula . You can just | |
16:40 | simply find the missing number . But let's confirm it | |
16:44 | . Using Pythagoras there , Let's prove that this is | |
16:47 | 12 . So we know that a squared plus B | |
16:54 | squared is equal to c squared . And our goal | |
16:56 | , let's say we're looking for B . So A | |
16:59 | . Is five . And the high pattern you see | |
17:01 | is 13 five squared is 25 13 square 13 times | |
17:07 | 13 is 1 69 . And if we subtract both | |
17:10 | sides by 25 , 169 -25 is 1 44 . | |
17:16 | So now we've got to take the square root of | |
17:17 | 144 which is 12 . So it pays to note | |
17:22 | the special by triangles . Here's another example . So | |
17:30 | let's say that the hypothesis is 10 And one of | |
17:36 | the sizes six . What is the miss inside ? | |
17:40 | Go ahead and pause the video and figure it out | |
17:44 | soon . Let's write the special triangles 3455 12 , | |
17:50 | 13 , 8 , 15 , 17 and so forth | |
17:54 | . Notice that if we take the 345 triangle and | |
17:57 | if we multiply everything by two , Notice what happens | |
18:03 | , we're going to get the 6810 triangles . So | |
18:07 | multiples of the 345 triangle also apply to a right | |
18:11 | triangle here . This is six . This is 10 | |
18:14 | . The missing number is eight , so X . | |
18:16 | Is eight . So let's prove that . So a | |
18:19 | squared plus B squared is equal to see square A | |
18:23 | is six . We're looking for being . And the | |
18:25 | hypothesis 10 six squared is 36 . 10 squared is | |
18:30 | 100 100 -36 is 64 . And the square root | |
18:34 | of 64 will give us the missing side which is | |
18:38 | eight . Yeah . So let me give you a | |
18:42 | few examples for all of these . Find the miss | |
18:45 | inside , find the value of X . You can | |
18:52 | get started with the first example . Okay , so | |
19:43 | let's start with the first one . The first one | |
19:46 | is associated with the 7 24 25 triangle . Therefore | |
19:50 | X . is 25 . Now for the 2nd 1 | |
19:54 | It's associated with the 8 15 17 Triangle , We | |
19:58 | have 15 and 17 . So the missing side has | |
20:01 | to be eight . Now for the 3rd 1 notice | |
20:07 | that It's proportional to the 345 triangle , It's not | |
20:12 | proportional to any other right triangle . So if we | |
20:15 | multiply these numbers by three , we're going to get | |
20:18 | two of the numbers that we have in the triangle | |
20:20 | three times 3 is nine , Four times three is | |
20:23 | 125 times streets 15 . So if you see two | |
20:27 | sides present , then you know , the third side | |
20:30 | has to be 12 . The next one is simply | |
20:34 | the nine . It's the 40 . Actually , I | |
20:38 | messed up on this one . I meant this to | |
20:40 | be nine . They're supposed to be the 9 40 | |
20:42 | 41 but I got mixed up with the 11 60 | |
20:45 | 61 soon . That's a bad problem , ignore it | |
20:49 | . Now , the next one is associated with the | |
20:51 | 5:12 13 triangle . If you multiply those numbers by | |
20:56 | two , It's gonna be five times 2 is 10 | |
21:01 | , 12 times two is 24 . 13 times two | |
21:05 | is 26 . So we have two of these numbers | |
21:09 | 10 and 26 . So the missing side has to | |
21:11 | be 24 . Now for the last one maybe dry | |
21:16 | because of all the clutter . This is 3040 . | |
21:21 | And we're looking for X . Notice that this is | |
21:23 | similar To the 345 triangle . So if you multiply | |
21:28 | three by 10 we get 34 by 10 40 . | |
21:31 | So five times 10 is 50 . So that partners | |
21:34 | is 50 . Here's another problem that you could try | |
21:37 | . A rectangle . A B C D . A | |
21:41 | B is 12 units along And AC . is 13 | |
21:46 | minutes long . What is the area of the rectangle | |
21:49 | ? Now rectangles , they form a 90° angles and | |
21:53 | look at the triangle that forms we have a right | |
21:55 | triangle If this is 12 and that's 13 . What | |
21:58 | is the most inside ? So we know this is | |
22:00 | the 5 12 13 triangle . So left B . | |
22:03 | CS five . So now we can find the area | |
22:06 | . The area of the rectangle is left times with | |
22:09 | The left is 12 , the width is five , | |
22:12 | So it's just 12 times five which is 16 . | |
22:16 | So as you can see you can find the answer | |
22:18 | quickly . If you know your special by triangles , | |
22:21 | you don't have to use the bathroom formula . If | |
22:24 | you commit this summer me it will save you a | |
22:25 | lot of time . And on the S . A | |
22:27 | . T . Test and on the T . Test | |
22:30 | time is a factor . So you want to find | |
22:33 | the answer quickly . |
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OVERVIEW:
Geometry Introduction - Basic Overview - Review For SAT, ACT, EOC, Midterm Final Exam is a free educational video by The Organic Chemistry Tutor.
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