Geometric Series and Geometric Sequences - Basic Introduction - By The Organic Chemistry Tutor
00:0-1 | in this video , we're going to focus on geometric | |
00:02 | sequences and series . So first let's discuss the difference | |
00:07 | between a geometric sequence and a geometric series . What | |
00:14 | do you think ? The differences ? Here's an example | |
00:19 | of a geometric sequence , The # 36 , 12 | |
00:25 | 24 48 and so forth . A geometric sequence is | |
00:31 | different from And the different sects sequence such as this | |
00:37 | one here . In that a geometric sequence has a | |
00:40 | common ratio versus a common difference . If you take | |
00:45 | the second term and divided by the first term six | |
00:49 | divided by three is too , you're gonna get the | |
00:51 | common ratio . If you take the third-term divided by | |
00:56 | the second term , you'll get the same common ratio | |
00:58 | . 12 divided by six . It's too . So | |
01:02 | that's the defining mark of a geometric sequence . In | |
01:05 | an arithmetic sequence , there's a common difference . If | |
01:09 | you take the second term and subtract it from the | |
01:12 | first term 8 -5 is dream . If you take | |
01:16 | the third term subtracted by the second , 11 -8 | |
01:19 | Extreme . So that's how you can distinguish an arithmetic | |
01:22 | sequence from a geometric sequence . And arithmetic sequence has | |
01:27 | a common difference between terms A geometric sequence has a | |
01:31 | common ratio between terms within an arithmetic sequence . You're | |
01:35 | dealing with addition and subtraction for a geometric sequence you're | |
01:40 | dealing with multiplication and division between terms . So now | |
01:47 | that we know what the geometric sequences and how to | |
01:50 | distinguish it from an arithmetic sequence . What is the | |
01:54 | geometric series ? A geometric series is basically the some | |
01:58 | of the numbers in a geometric sequence . So three | |
02:02 | plus 6 plus 12 plus 24 and so forth would | |
02:08 | be a geometric series . This is the first term | |
02:14 | , this is the second term , this is the | |
02:16 | third and so forth . Now the former you need | |
02:23 | to calculate the f term of a geometric sequence or | |
02:27 | series . It's the first term a sub one Times | |
02:32 | The Common Ratio . Our Race to the N -1 | |
02:35 | . So for instance , Let's just make a note | |
02:42 | that R . is equal to two . Let's say | |
02:47 | we want to find the value of the fifth term | |
02:49 | . We know the fifth term is 48 . But | |
02:51 | let's go ahead and calculate . So you can see | |
02:54 | how this formula works . So the first term is | |
02:57 | three . Are the common ratio is too and n | |
03:02 | is the sub script here . We're looking for the | |
03:03 | fifth term soon and it's five . So 5 -1 | |
03:09 | is four , two to the fourth power . If | |
03:13 | you multiply 24 times two times two times two times | |
03:16 | two . That's 16 . 16 Times Street is 48 | |
03:22 | . So that's the function of this formula . It | |
03:25 | gives you the value of the F . Term . | |
03:28 | So you can find the value of the eighth term | |
03:30 | , the 20th term and so forth . The next | |
03:35 | equation you need to be familiar with 1st . Let's | |
03:38 | get rid of this . The next equation is the | |
03:47 | partial sum formula . The partial son of a geometric | |
03:52 | series is the first term times 1 - Our race | |
03:56 | to the end over one minus R . So let's | |
04:01 | say that we want to find the some of the | |
04:03 | first five terms . This is going to be three | |
04:07 | plus six plus 12 plus 24 plus 48 . Go | |
04:15 | ahead and plug that into a calculator . So for | |
04:23 | the first five terms I got the partial summers being | |
04:26 | 93 . Now let's confirm that with this equation . | |
04:33 | So let's calculate S Sub five . The first chemistry | |
04:38 | Times 1 - R . RS two and it's five | |
04:44 | Divided by 1 - are . So that's 1 -2 | |
04:51 | . 2 to the 5th power . That's 32 . | |
04:55 | 1 -2 is -1 . Now 1 -32 is negative | |
05:01 | . 31 Three times negative . 31 that's -93 but | |
05:07 | divided by -1 . That becomes positive 93 . So | |
05:13 | we get the same answer . So any time you | |
05:15 | need to find the son of a finite series , | |
05:21 | you could use this formula . So this series here | |
05:27 | is finite . We're looking for the some of the | |
05:30 | first five terms . There's a beginning and there's an | |
05:33 | end . This series here is not finite . It's | |
05:40 | an infinite geometric series . The reason being is because | |
05:44 | of the dot dot dot that we see here it | |
05:46 | goes on forever . It doesn't stop at the fifth | |
05:48 | term . It keeps on going to infinity . So | |
05:50 | it's an infinite geometric series . This is an infinite | |
05:57 | geometric sequence . It's a sequence that goes on forever | |
06:01 | and its geometric . So make sure you can identify | |
06:04 | if a sequence is arithmetic geometric ? Is it finite | |
06:08 | infinite ? Is it a sequence or series ? Now | |
06:25 | the next thing we need to talk about is the | |
06:29 | arithmetic mean And the geometric mean . Let's call the | |
06:35 | arithmetic mean . Emma The arithmetic mean is simply the | |
06:39 | average of two numbers . The geometric for me let's | |
06:43 | call it M . G . Is the Square Root | |
06:47 | of the Product of two Numbers . So let's go | |
06:51 | back to the arithmetic sequence that we had here . | |
06:58 | If we wanted to find the arithmetic mean between the | |
07:02 | first and the third term , it will give us | |
07:05 | the middle number , the second term . If you | |
07:08 | average five and 11 and divide by two . Using | |
07:11 | this formula You're gonna get 16/2 which is eight . | |
07:18 | So the US when you find the arithmetic mean of | |
07:20 | the first term and the third term you're going to | |
07:24 | get the second term because the average of one in | |
07:26 | three is too Yeah . Now let's find the right | |
07:35 | protect me between the first and the fifth term . | |
07:38 | This will give us The middle term 11 . So | |
07:47 | if we were to add up a one and a | |
07:49 | five and then divided by two . If we were | |
07:52 | to get the average we will get a three , | |
07:55 | the average of one in five history . So let's | |
07:59 | add five and 17 and then divided by two . | |
08:02 | five plus 17 is 22 , 22 , divided by | |
08:06 | two is 11 . So that's the concept of the | |
08:09 | rhythm technique . Whenever you take the arithmetic mean of | |
08:14 | two numbers within an arithmetic sequence , you get the | |
08:17 | middle term of that of those two numbers that you | |
08:19 | selected . Now the same is true for a geometric | |
08:22 | sequence . If we were to find the geometric mean | |
08:25 | between three and 12 , You'll get the Middle # | |
08:28 | six . If we wanted to find the geometric mean | |
08:31 | between three and 48 , We would get the Middle | |
08:34 | # 12 . So let's confirm that . Let's find | |
08:38 | the geometric mean Between a one and a three . | |
08:46 | So the first term is three . The third term | |
08:49 | is 12 , Three times 12 is 36 . The | |
08:54 | square root of 36 is six . So we get | |
08:57 | the middle number . Now let's find the geometric mean | |
09:02 | between the first term and the fifth term . So | |
09:08 | we should get 12 as an answer . So the | |
09:13 | average of one in 51 plus five or six divided | |
09:16 | by two . A street . So we should get | |
09:18 | a sub three . The first term is three . | |
09:22 | The last term or the fifth term is 48 . | |
09:26 | Now , What's three times 48 ? If you're not | |
09:29 | sure what you could do is break it up into | |
09:32 | smaller numbers . 48 is three times 16 Three times | |
09:37 | three is 9 . So you have the square root | |
09:39 | of nine times the square root of 16 . The | |
09:42 | square root of nine . History . The square root | |
09:45 | of 16 is 43 times four is 12 . So | |
09:50 | the geometric mean of three and 48 Is the middle | |
09:55 | number in the geometric sequence , which is 12 . | |
10:04 | Now , sometimes you need to be able to write | |
10:06 | equations between terms within a geometric sequence . For instance | |
10:13 | , if you want to relate the second equation two | |
10:16 | , the first equation , you need to multiply by | |
10:17 | our I mean the second term to the first term | |
10:22 | . If you want to relate the fifth term to | |
10:25 | the second term , you need to multiply by our | |
10:27 | cube To go from the second term to the 5th | |
10:30 | term . You need to multiply it by our three | |
10:33 | times . If you multiply six by , are you | |
10:36 | gonna get 12 ? If you multiply 12 by are | |
10:39 | you get 24 24 by our You get 48 . | |
10:43 | So to go from the second term to the fifth | |
10:45 | term you need to multiply by our cube . And | |
10:49 | the reason why it's Cuba is because the difference between | |
10:51 | five and to a street and you can check that | |
10:59 | . So if you take the second term which is | |
11:01 | six multiplied by two to the third . That's six | |
11:04 | times eight which is 48 . And that gives you | |
11:06 | the 5th time . So if I want to relate | |
11:13 | the ninth term To the 4th term , how many | |
11:16 | are values do I got to multiply the fourth time | |
11:18 | to get to the nighttime ? 9 -4 is five | |
11:23 | . So I got to multiply the fourth term by | |
11:25 | our to the fifth power to get the ninth term | |
11:29 | . So make sure you know how to write those | |
11:30 | formulas . So we've discussed calculated to some of a | |
11:40 | finite series . Just review if you want to calculate | |
11:44 | the sum Of a finite series , one that has | |
11:47 | a beginning and an end . You would use this | |
11:51 | formula now . What about the sun of an infinite | |
11:55 | ? Serious ? How can we find that ? What's | |
12:00 | the formula that we need to calculate us to infinity | |
12:05 | ? It's basically this same formula . But without that | |
12:08 | part it's a 1/1 minus R . So here's two | |
12:18 | examples of an infinite geometric series . This is one | |
12:21 | of them and this one is going to be another | |
12:24 | one , 84 21 one half and so forth . | |
12:33 | We can't calculate the sum of both infinite geometric series | |
12:38 | For this one . RS 2 . So our or | |
12:43 | rather the absolute value of R . Is greater than | |
12:45 | one . When that happens , the geometric series diverges | |
12:52 | which means you can't calculate the sum because it doesn't | |
12:58 | it doesn't converge to a specific value . If you | |
13:01 | keep adding these numbers it's not gonna converged to a | |
13:05 | value . It's going to get bigger and bigger and | |
13:07 | bigger . So the series diverges . If you try | |
13:12 | to calculate it let's say you plugged in one for | |
13:14 | a one and mhm to for our it's not going | |
13:19 | to work , you get three over negative one which | |
13:22 | is negative three . And clearly that's not the some | |
13:24 | of this series . The fact that you get a | |
13:29 | negative some from positive numbers tells you something is wrong | |
13:32 | . So this formula doesn't work if the series diverges | |
13:37 | , it only works if the series converges and that | |
13:39 | happens when the absolute value of our is less than | |
13:42 | one . If we focus on this particular infinite geometric | |
13:47 | series , notice the value of our if we take | |
13:51 | the second term divided by the first term , 4/8 | |
13:55 | is one half . If we take the third term | |
13:57 | divided by the second term To over four reduces 2 | |
14:01 | 1/2 . That's the value of our . So for | |
14:06 | that particular series we could say that the absolute value | |
14:10 | of art , which is one half , that's less | |
14:12 | than one . Therefore the series converges , which means | |
14:19 | we can calculate a sum . It has a finite | |
14:22 | some . Even though the numbers get smaller and smaller | |
14:24 | and smaller , now let's calculate the sun . So | |
14:31 | the sum of an infinite number of terms of this | |
14:35 | geometric series is going to be the first term . | |
14:37 | A suborn which is a Over 1 -2 . Where | |
14:41 | are is a half ? 1 -1 half is one | |
14:46 | half . So multiplying the top and bottom by two | |
14:49 | , we get 16 on top . These two will | |
14:52 | cancel . We get one . So the some of | |
14:55 | this infinite geometric series that converges is 16 . So | |
15:02 | that's how you can calculate the sum of an infinite | |
15:04 | geometric series . The series must converge and for that | |
15:09 | to happen , the absolute value of art has to | |
15:11 | be less than one . If it's greater than one | |
15:14 | , the series will diverge and you won't be able | |
15:16 | to calculate the sum . Now let's work on some | |
15:19 | practice problems . Right ? The first five terms of | |
15:23 | each geometric sequence shown below . So let's start with | |
15:28 | the first one . The first term is to to | |
15:33 | find the next term . We need to multiply the | |
15:37 | first term by the common ratio . The second term | |
15:39 | is equal to the first term times the common ratio | |
15:43 | . So two times 3 is six . And then | |
15:46 | to get the third term , we just got to | |
15:48 | multiply the second term by the common ratio , six | |
15:51 | times 3 is 18 , 18 . Times Street is | |
15:54 | 54 And then 54 times street . That's 1 62 | |
16:00 | . So that's the answer for number one . Now | |
16:07 | , let's move on to number two . The first | |
16:12 | term is 80 . The common ratio is 1/2 . | |
16:16 | So we're gonna multiply 80 by a half , Half | |
16:19 | of 80 is 40 , Half of 40 is 20 | |
16:22 | , Half of 2010 . Half of tennis five . | |
16:25 | So those are the first five terms for the second | |
16:28 | geometric sequence . Now let's move on to number three | |
16:34 | . So the first term is six to find the | |
16:36 | next term , we need to multiply six by -2 | |
16:40 | . So this is gonna be negative 12 negative 12 | |
16:43 | times negative two is positive 24 . And then it's | |
16:46 | just going to alternate . So whenever you see a | |
16:50 | sequence , a geometric sequence with alternative science , then | |
16:55 | you know that the common ratio must be negative number | |
16:59 | two . Right . The first five terms of the | |
17:02 | geometric sequence defined by the recursive formula shown below . | |
17:08 | So we're given the first term When N is too | |
17:12 | we have that . The second term is equal to | |
17:15 | negative four time is the first term , and we | |
17:19 | know that the second term is the first term . | |
17:21 | Times are . So therefore are the common ratio must | |
17:26 | be negative for so any time you need to write | |
17:30 | a recursive formula of a geometric sequence , it's going | |
17:33 | to be a sub N is equal to our Times | |
17:37 | . The previous term , a 7 -1 . The | |
17:40 | next term is always the previous term times the common | |
17:42 | ratio . Mhm . So the common ratio is this | |
17:50 | number -4 . So once we have the first term | |
17:56 | in the common ratio , we can easily right out | |
17:57 | the sequence . So the first term is negative three | |
18:00 | . The second term will be negative three times negative | |
18:03 | four , which is 12 . The third term will | |
18:07 | be 12 times -4 , which is -48 . The | |
18:13 | fourth term is negative 48 times negative four , Which | |
18:17 | is 192 . And then the 5th term 92 times | |
18:23 | negative four . His negative 7 68 . So that's | |
18:29 | how we can write the first five terms of the | |
18:30 | geometric sequence defined by recursive formula . It's by realizing | |
18:34 | that this number is the common ratio , write a | |
18:39 | general formula that gives the f term of each geometric | |
18:43 | sequence And then calculate the value of the 8th term | |
18:47 | of each of those geometric sequences . So let's start | |
18:52 | with number one . So we have the number 6 | |
18:58 | 24 , 96 3 84 and so forth . The | |
19:04 | first thing we need to do is calculate the common | |
19:06 | ratio . So let's divide the second term by the | |
19:10 | first term , Dividing 24 x six . We get | |
19:16 | four . Now just to confirm that this is indeed | |
19:23 | a geometric sequence , let's take the third term and | |
19:27 | divided by the second term , not the first one | |
19:31 | , So 96 divided by 24 And that is also | |
19:37 | equal to four . So we have a geometric sequence | |
19:40 | here in order to write the formula . All we | |
19:47 | need is the value of the first term and the | |
19:49 | common ratio . So we could use this equation . | |
19:53 | The f term is going to be equal to the | |
19:55 | first term times are Race to the N -1 . | |
20:00 | The first term being six . R . is four | |
20:06 | , So we can write it as a . seven | |
20:08 | is equal to six Times for Race 2 & -1 | |
20:13 | . So this is the answer for part A . | |
20:15 | For the first sequence . Now let's move on the | |
20:22 | part B . Let's calculate the value Of the 8th | |
20:25 | term . So we just gotta plug in eight into | |
20:28 | end . So it's six times 4 . Race to | |
20:32 | the 8 -1 . 8 -1 is seven . four | |
20:37 | . race to the seven power is 16,384 Times six | |
20:44 | . This gives us 98,304 . So that is the | |
20:53 | value of the 8th term and you could confirm it | |
20:58 | . If you keep multiplying these numbers by four , | |
21:03 | you're going to get it 3 84 Times four , | |
21:07 | that's 1536 . That's the fifth term . A few | |
21:12 | times about four . again You get 61 44 Times | |
21:18 | four You get 24 576 And then times four gives | |
21:24 | you this number . Now let's move on to number | |
21:29 | two . So we have the sequence five -1545 -135 | |
21:46 | and so forth . So the first term is five | |
21:51 | . The common ratio which can be calculated by taking | |
21:56 | the second term divided by the first term . That's | |
21:58 | -15 divided by five . That's negative three . Are | |
22:03 | is also equal to the third term divided by the | |
22:05 | second term . So that's 45 Over -15 which is | |
22:11 | -3 . So the value the first term is five | |
22:19 | are is negative three . So now let's go ahead | |
22:25 | and write a general formula that gives us the end | |
22:28 | after . So a seven is going to be a | |
22:32 | someone times are raised to the N -1 . The | |
22:36 | first term is five . R is -3 . So | |
22:42 | this right here is the answer for part A Now | |
22:46 | part B calculate the value of the 8th term . | |
22:49 | So let's replace and with eight negative three raised to | |
23:01 | the center of power . That's -2187 . Multiplying that | |
23:08 | by five . This gives us negative 10,000 935 . | |
23:15 | So that's the final answer . For part B . | |
23:18 | Number four describe each pattern of numbers as arithmetic or | |
23:22 | geometric finite or infinite sequence . Or serious . Just | |
23:28 | looking at the 1st 1 . Do we have a | |
23:30 | common difference or common ratio ? Going from 4 to | |
23:34 | 8 ? We increased by four . From 8 to | |
23:37 | 12 . That's an increase by four And 12 - | |
23:40 | 16 . So we're constantly adding for we're not multiplying | |
23:44 | by four . So therefore we have a common difference | |
23:49 | and not a common ratio . So because we have | |
23:52 | a common difference , this is arithmetic , not geometric | |
23:59 | . We're dealing with addition rather than multiplication . Now | |
24:04 | is this a sequence or series ? We're not adding | |
24:07 | numbers . So we have a sequence . If you | |
24:13 | see a comma between the numbers , it's gonna be | |
24:15 | a sequence . If you see a plus you're dealing | |
24:18 | with a series . Now , is this sequence finite | |
24:22 | or infinite . It has a beginning and it has | |
24:25 | an end . We don't have dots to indicate that | |
24:28 | it goes on forever . So this is finite . | |
24:31 | So we have a finite arithmetic sequence for number one | |
24:36 | . Now let's move on to number two , going | |
24:39 | from 90 to 30 . That's a difference of negative | |
24:42 | 60 Going from 30 to 10 . That's a difference | |
24:45 | of -20 . So we don't have a common difference | |
24:47 | here . If we divide the second term by the | |
24:51 | first term , This reduces to 1/3 . If we | |
24:54 | divide the third term by the second term , that's | |
24:57 | also 1/3 . So what we have here is a | |
25:01 | common ratio rather than a common difference . So the | |
25:06 | pattern of numbers is geometric , not arithmetic . We're | |
25:10 | multiplying by 1/3 to get the second term from the | |
25:13 | first term . Now , are we dealing with a | |
25:17 | sequence or serious ? So we don't have a plus | |
25:21 | sign between the numbers . So we have a comma | |
25:23 | so dealing with a sequence and this sequence has no | |
25:28 | end . It goes on forever . So what we | |
25:31 | have here is an infinite geometric sequence . Now . | |
25:37 | For number three , we could see that we have | |
25:43 | a common ratio of two . Five times two is | |
25:47 | 10 , 10 times two is 2020 times two is | |
25:50 | 40 . So this is geometric . Now there's a | |
25:57 | plus between the numbers . So this is going to | |
25:59 | be a series , not a sequence . And this | |
26:03 | sequence , I mean the series rather comes to an | |
26:05 | end . The last number is 80 . So it's | |
26:07 | not infinite , but it's finite . So we have | |
26:10 | a finite geometric series For the last one . We | |
26:15 | can see that we have a common difference of -450 | |
26:19 | -4 . It's 46 46 runners four is 42 . | |
26:24 | So this is going to be arithmetic . We have | |
26:29 | a plus between the numbers so it's a series and | |
26:33 | it goes on forever . So it's infinite . So | |
26:38 | we have an infinite of reference six series number five | |
26:43 | Find the sum of the 1st 10 terms of the | |
26:45 | geometric sequence shown below . So the first term is | |
26:52 | seven . The common ratio -14 divided by seven . | |
26:58 | That's negative too . 28 divided by -14 is also | |
27:03 | negative too . So now that we know the first | |
27:06 | time in the common ratio , we can calculate the | |
27:08 | Sun using this format . So it's the first term | |
27:12 | times 1 - Our race to the end Over 1 | |
27:16 | -2 . To the some of the 1st 10 terms | |
27:20 | . It's going to be the first term seven times | |
27:22 | one minus negative two . Now it's a race to | |
27:27 | the end power and is 10 And then divided by | |
27:31 | 1 -2 . Negative two . Raised to the 10th | |
27:44 | power . That's positive 1,024 . And here we have | |
27:51 | one minus negative two which is one plus two . | |
27:54 | And that stream 1 -1024 . That's negative . 1000 | |
28:02 | 23 . Seven times negative 10 23 . Divided by | |
28:10 | three . That's -2387 . So that's the final answer | |
28:20 | . Travis problem . Find the some of the infinite | |
28:22 | geometric series . So we have the numbers 270 , | |
28:29 | 90 30 10 and so forth . So we can | |
28:36 | see that the first term A someone That's 270 . | |
28:41 | The common ratio . If we divide 90 x 70 | |
28:45 | , what does that simplify too ? I mean 90 | |
28:48 | x 2 70 . Well , we could cancel a | |
28:51 | zero . So we get 9/27 . 9th Street Time | |
28:55 | Street 27 is nine Times Street . That becomes true | |
28:59 | over nine three . We can write that is three | |
29:03 | times 19 is three Times street , this is one | |
29:05 | third . So that's going to be the common ratio | |
29:11 | . And of course if you divide 30 x 90 | |
29:14 | , you also get one third . So now that | |
29:18 | we have the first term and the common ratio , | |
29:21 | we can now calculate the some of the infinite geometric | |
29:27 | series . Using this formula , it's going to be | |
29:30 | a sub 1/1 -2 . By the way , this | |
29:36 | particular infinite geometric series , there's a converge or diverge | |
29:41 | And the absolute value of our is less than one | |
29:44 | . It's 1/3 , which is about .333 or .3 | |
29:48 | repeating . So because it's less than one , the | |
29:52 | infinite geometric series converges . We can calculate the sum | |
29:58 | the sum is finite . So let's go ahead and | |
30:02 | calculate that some . The first term is 2 70 | |
30:06 | are is one third . So what's 1 -1 3 | |
30:12 | 1 ? If you multiply it by three of the | |
30:14 | three , You get through every 3 -1 of the | |
30:18 | three which is two or three . Now what I'm | |
30:24 | gonna do is I'm gonna multiply the top and bottom | |
30:26 | by three . These stories will cancel . So it's | |
30:32 | gonna be 2 70 Time Street divided by two to | |
30:42 | 70 divided by two . Is 1 35 1 35 | |
30:45 | Times Street . That's gonna be 405 . So that | |
30:51 | is the sum of this infinite geometric series . |
DESCRIPTION:
This video provides a basic introduction into arithmetic sequences and series. It explains how to find the nth term of a sequence as well as how to find the sum of an arithmetic sequence. It also discusses how to distinguish a finite sequence from an infinite series. It also includes a few word problems.
OVERVIEW:
Geometric Series and Geometric Sequences - Basic Introduction is a free educational video by The Organic Chemistry Tutor.
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