Pythagorean Theorem | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Pythagorean Theorem | MathHelp.com - Free Educational videos for Students in K-12


Pythagorean Theorem | MathHelp.com - By MathHelp.com



Transcript
00:0-1 to find the value of X . In this example
00:03 , notice that we have a right triangle , so
00:05 we can use the Pythagorean theorem . The pythagorean theorem
00:09 states that the sum of the squares of the lengths
00:12 of the legs of a right triangle is equal to
00:15 the square of the length of the hypotenuse , or
00:19 a squared plus B squared equals c squared where A
00:27 and B . Are the lengths of the legs of
00:29 the right triangle , and C . Is the length
00:31 of the hypotenuse . So here , since the legs
00:35 of the right triangle have length six and eight ,
00:38 and the hypotenuse has a length of X , we
00:41 can set up the equation six squared plus eight squared
00:47 equals x squared simplifying from here , six squared is
00:53 six times six or 36 8 squared is eight times
00:58 eight or 64 . So we have 36 plus 64
01:04 equals x squared . Next 36 plus 64 is 100
01:11 , And we have 100 equals x squared . Now
01:16 to get X by itself , since x is squared
01:19 , we take the square root of both sides of
01:21 the equation . On the right , the square root
01:25 of X squared is X . And on the left
01:29 , since 100 is the perfect square 10 times 10
01:33 , the square root of 100 is 10 , So
01:36 10 equals x . Notice that we don't use plus
01:43 or minus 10 because X represents the length of the
01:46 hypotenuse of the triangle , which cannot be negative ,
01:50 So the value of X is 10 .
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