Mixture Word Problems | MathHelp.com - By MathHelp.com
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00:0-1 | The mad scientist has one solution that is 30 acid | |
00:05 | and another that's 18 acid . How much of each | |
00:10 | should he use to get 300 liters of a solution | |
00:14 | ? That's 21 acid . Well let's start things off | |
00:19 | by setting up a chart across the top . We | |
00:23 | have our mixture formula which in this case is amount | |
00:27 | of solution times percent acid equals amount of acid . | |
00:33 | Down the left side . We have are two different | |
00:36 | types of solutions that add to our final mixture . | |
00:42 | So for our amount of solution column We know that | |
00:45 | we have 300 litres in our final mixture . So | |
00:50 | we can split up the amount of solution for each | |
00:53 | of our original solutions as X and 300 minus X | |
01:03 | . For our percent acid column . We have 30 | |
01:07 | which is .30 or 0.3 18% , which is point | |
01:16 | 18 And we know that our mixture is 21 acid | |
01:22 | or point 21 based on our formula , we now | |
01:27 | multiply the first two columns together To fill out the | |
01:31 | 3rd column of the chart and we have 0.3 x | |
01:38 | .18 times parentheses , 300 - X . and 300 | |
01:46 | times point to one which is 63 for our equation | |
01:55 | we use the idea that the amount of acid in | |
01:59 | each of our solutions will add to the amount of | |
02:03 | acid in our final mixture . So that's .3 x | |
02:10 | . Mhm . Yeah plus 0.18 Yeah , Times 300 | |
02:18 | -1 equals 63 solving from here . I would first | |
02:26 | multiply both sides of the equation By 100 to get | |
02:31 | rid of the decimals and eventually we find That x | |
02:35 | equals 75 . Going back to our chart , X | |
02:42 | represents the amount of 30 solution that we have . | |
02:47 | So we know we have 75 leaders of 30 solution | |
02:57 | . There are 18 solution . We have 300 -100 | |
03:03 | -75 which is 225 l Of 18 solution . |
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