Area of a Rectangle | MathHelp.com - Free Educational videos for Students in K-12

Area of a Rectangle | MathHelp.com - By MathHelp.com

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00:0-1	A rectangle has a diagonal of 10 cm and a
00:04	length of eight cm . Find the area of the
00:08	rectangle . Let's start this problem by drawing a picture
00:13	of the rectangle . Yeah , Its diagonal is 10
00:29	cm . Yeah , mm . Its length is eight
00:35	cm and we're asked to find its area remember that
00:41	the formula for the area of a rectangle is length
00:45	times with And were given that the length of the
00:52	rectangle is eight cm . But we don't know the
00:56	width which we can label in our diagram as W
01:01	. To find the value of W . Notice that
01:04	a right triangle is formed in the lower right of
01:07	the figure . And since we know the lengths of
01:10	two sides of the right triangle , we can use
01:14	the pythagorean theorem to find the length of the third
01:17	side . So we have eight squared plus W squared
01:25	equals 10 squared or 64 plus W squared equals 100
01:36	. and subtracting 64 from both sides , gives us
01:45	W squared equals 36 . And square rooting both sides
01:53	, We find that w equals six . Now that
02:00	we know that the width of the rectangle is six
02:04	, we can find the area of the rectangle ,
02:07	which is the length times the width , or eight
02:11	times 6 , Which is 48 . So the area
02:19	of the rectangle is 48 square cm . Notice that
02:29	we include square centimeters in our final answer , because
02:34	we were given centimeters is our units in the original
02:37	problem .

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