Trigonometry Word Problems | MathHelp.com - By MathHelp.com
Transcript
00:0-1 | Neil sees a rocket at an angle of elevation of | |
00:04 | 11°. . If Neil is located five miles from the | |
00:09 | rockets launch pad , how high is the rocket round | |
00:13 | ? Your answer to the nearest 100 ? Let's start | |
00:18 | this problem by drawing a picture . We have Neil | |
00:24 | . Who sees a rocket ? Yeah . At an | |
00:29 | angle of elevation of 11°. . Notice that an angle | |
00:38 | of elevation is formed from the ground up word where | |
00:42 | one side of the angle is the horizontal segment along | |
00:46 | the ground And the other side of the angle is | |
00:50 | rotated 11° upward from the ground . Now , to | |
00:56 | complete our picture were also given that Neil is five | |
01:00 | miles from the rockets launch pad . So neal is | |
01:04 | five miles from a point directly below the rocket , | |
01:09 | please . And we're asked to find the height of | |
01:13 | the rocket so we can use X to represent its | |
01:17 | height to find the value of X . Notice that | |
01:22 | Neil the launch pad and the rocket form a right | |
01:25 | triangle . So using the 11 degree angle were given | |
01:32 | that the side opposite the 11 degree angle has a | |
01:36 | length of X . In the side adjacent to the | |
01:40 | 11° Angle has a length of five . And remember | |
01:44 | that tangent equals opposite over adjacent . Yes . So | |
01:54 | we can set up the equation . The tangent of | |
01:57 | 11° equals x over five . Yes . Yeah , | |
02:08 | Solving for X . We multiply both sides of the | |
02:12 | equation by five . Yes . Yeah . On the | |
02:22 | right side the fives cancel and we're left with X | |
02:28 | . And on the left side we have five times | |
02:31 | the tangent of 11°. . Yeah . Now plugging this | |
02:39 | into our calculator and rounding to the nearest 100s , | |
02:43 | gives us .97 equals x . So the height of | |
02:54 | the rocket is .97 miles . |
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