Ratio Word Problems | MathHelp.com - By MathHelp.com
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00:0-1 | A piece of string that is 63 long is cut | |
00:04 | into three parts such that the lengths of the parts | |
00:08 | of the string are in the ratio 5-6-10 . Find | |
00:13 | the lengths of the three parts . Since the three | |
00:17 | parts of the string are in the ratio 5-6 to | |
00:21 | 10 We can represent the parts as five X . | |
00:28 | Six X . And 10 X . So let's call | |
00:33 | five X . Our first part of the string and | |
00:41 | six X . Our second part And 10 x our | |
00:49 | 3rd part . Now , since we know that the | |
00:56 | original piece of string with 63 long are three parts | |
01:02 | must add to 63" . So we can set up | |
01:06 | the equation five x plus six X plus 10 X | |
01:14 | equals 63 . Simplifying on the left side gives us | |
01:21 | 21 x equals 63 And dividing both sides by 21 | |
01:30 | X equals three . Yeah So the length of the | |
01:36 | first part of the string , five x is five | |
01:41 | times 3 or 15 inches and the length of the | |
01:49 | second part of the string , six X . Is | |
01:52 | six times three or 18 inches and the length of | |
02:01 | the third part of the string 10 X . Is | |
02:04 | 10 times three or 30 inches . Yes . Finally | |
02:17 | make sure to check the answer back in the original | |
02:20 | problem to see if it makes sense in this case | |
02:24 | 15 plus 18 plus 30 equals 63 . So our | |
02:31 | answer checks . |
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