Geometry Concepts | MathHelp.com - By MathHelp.com
Transcript
| 00:0-1 | A 35-foot ladder is leaning against the side of a | |
| 00:04 | building and is positioned such that the base of the | |
| 00:07 | ladder is 21 ft from the base of the building | |
| 00:12 | . How far above the ground is the point where | |
| 00:15 | the latter touches the building ? Let's start this problem | |
| 00:19 | by drawing a picture of the building . Yeah , | |
| 00:26 | yeah , with the latter leaning against it . Yeah | |
| 00:34 | , We know that the length of the latter is | |
| 00:37 | 35 ft . The distance between the base of the | |
| 00:42 | ladder and the base of the building is 21 ft | |
| 00:47 | . And were asked how far above the ground is | |
| 00:50 | the point where the latter touches the building . So | |
| 00:53 | let's use X to represent this distance . Notice that | |
| 00:58 | we have a right triangle . So we can use | |
| 01:03 | the pythagorean theorem , A squared plus B squared equals | |
| 01:10 | C squared . So we have 21 squared plus X | |
| 01:18 | squared equals 35 squared , Solving from here , 21 | |
| 01:26 | squared is 441 And 35 squared is 1,225 . So | |
| 01:36 | we have 441 plus X squared equals 1225 . Notice | |
| 01:46 | that you may want to use a calculator in problems | |
| 01:49 | such as this one , since the numbers were working | |
| 01:52 | with are fairly large next to get the X square | |
| 01:57 | term by itself . We subtract 441 from both sides | |
| 02:03 | . Yes , And we have x squared equals 784 | |
| 02:13 | and square rooting both sides , We find that x | |
| 02:18 | equals 28 . So the point where the latter touches | |
| 02:25 | the building is 28 ft above the ground . |
Summarizer
DESCRIPTION:
This lesson covers solving multi step equations. Students learn to solve equations that involve the distributive property by first distributing through the parentheses, then combining like terms, then solving from here. Students are also reminded to show all steps when solving equations.
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