Sum of Interior Angles of a Polygon | MathHelp.com - By MathHelp.com
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| 00:0-1 | In this problem were given that a polygon has 17 | |
| 00:05 | sides and were asked to find the sum of the | |
| 00:08 | measures of its interior angles . Remember that the formula | |
| 00:14 | for finding the sum of the measures of the interior | |
| 00:18 | angles of a polygon Is 180 times in -2 , | |
| 00:26 | Wherein represents the number of sides . So here , | |
| 00:32 | since our polygon has 17 sides , we can plug | |
| 00:37 | a 17 in for the in in our formula And | |
| 00:41 | we have a 180 times 17 -2 simplifying inside the | |
| 00:52 | parentheses first 17 -2 is 15 , So we have | |
| 00:59 | 180 times 15 , Which is 2700 . So if | |
| 01:09 | a polygon has 17 sides , then the sum of | |
| 01:13 | the measures of its interior angles is 2700°. . Note | |
| 01:24 | that you may want to use a calculator in this | |
| 01:26 | section . Since the numbers you'll be working with will | |
| 01:30 | be fairly large . |
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